Volume of cylinder / Volume of cone = 3/1
Let breadth = x metres.
Then, length = (x + 20) metres.
Perimeter = 5300 m = 200 m. 26.50
2[(x + 20) + x] = 200
2x + 20 = 100
2x = 80
x = 40.
Hence, length = x + 20 = 60 m.
Area of the park = (60 x 40) = 2400 sq.m
Area of the lawn = 2109 sq.m
Area of the crossroads = (2400 - 2109) = 291 sq.m
Let the width of the road be x metres. Then,
60x + 40x - (x * x) = 291
=>(x * x) - 100x + 291 = 0
=>(x - 97)(x - 3) = 0
=>x=3
Slant surface of a pyramid=1/2 perimeter of base slantheight
=1/2 x (4 x Side of squarebase) x Slantheight
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