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- Question
The area of a semicircle is 1925 sq.cm. Calculate its perimeter (in cm).
Options- A. 360
- B. 80
- C. 160
- D. 180
- Correct Answer
- 180
- 1. Considering two opposite vertices of a square of side ?a? as centres, two circular arcs are drawn within the square joining the other two vertices, thus forming two sectors. What is the common area in these two sectors?
Options- A. a2?+12
- B. a
- C. a2?2-1
- D. ?a/2 Discuss
- 2. The volume of a spherical balloon is increased by 700%. What is the percentage increase in its surface area?
Options- A. 300%
- B. 400%
- C. 450%
- D. 500% Discuss
- 3. In ?PQR, PQ = PR = 18 cm, AB and AC are parallel to lines PR and PQ respectively. If A is the mid-point of QR, then what is the perimeter (in cm) of quadrilateral ABPC?
Options- A. 18
- B. 28
- C. 32
- D. 36 Discuss
- 4. If ?ABC is an equilateral triangle of side 16 cm, then the length of altitude is
Options- A. 2?3 cm
- B. 4?3 cm
- C. 8?3 cm
- D. 5?3 cm Discuss
- 5. The base of a pyramid is a rectangle whose length and breadth are 16 cm and 12 cm respectively. If the length of all the lateral edges passing through the vertex of the right rectangular pyramid is 26 cm, then find the volume of the pyramid in cubic centimeter?
Options- A. 1536
- B. 1024
- C. 718
- D. 2072 Discuss
- 6. At what point does the line 3x + y = -6 intercept the x-axis?
Options- A. (2,0)
- B. (-2,0)
- C. (0,-6)
- D. (0,6) Discuss
- 7. The volume of metallic cylindrical pipe of uniform thickness is 748 c.c. Its length is 14 cm and its external radius is 9 cm. The thickness of the pipe is
Options- A. 0.5 cm
- B. 1.5 cm
- C. 1 cm
- D. 2 cm Discuss
- 8. If the volume of a cylinder is 3850 cubic cm and height is 25 cm, what is its radius? (Take ? = 22/7)
Options- A. 7 cms
- B. 14 cms
- C. 10 cms
- D. 3.5 cms Discuss
- 9. Dodecahedron has 30 edges. How many vertices does it have?
Options- A. 12
- B. 16
- C. 20
- D. 10 Discuss
- 10. A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?
Options- A. 2.91 m
- B. 3 m
- C. 5.82 m
- D. None of these Discuss
Volume and Surface Area problems
Search Results
Correct Answer: a2?2-1
Correct Answer: 300%
Correct Answer: 36
Correct Answer: 8?3 cm
Correct Answer: 1536
Correct Answer: (-2,0)
Correct Answer: 1 cm
Correct Answer: 7 cms
Correct Answer: 20
Correct Answer: 3 m
Explanation:
Area of the park = (60 x 40) = 2400 sq.m
Area of the lawn = 2109 sq.m
Area of the crossroads = (2400 - 2109) = 291 sq.m
Let the width of the road be x metres. Then,
60x + 40x - (x * x) = 291
=>(x * x) - 100x + 291 = 0
=>(x - 97)(x - 3) = 0
=>x=3
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