Let l, b the sides of the base, so that the area of the base = lb
remains constant.
Let ?h? be the height of the solid.
Volume of the solid, V = l× b× h.
Since the volume is to be increased by 50%
Volume of water flowing through 1 pipe of diameter x = Volume discharged by 6 pipes of diameter 12 cms.
As speed is same, area of cross sections should be same.
Area of bigger pipe of diameter x = Total area of 6 smaller pipes of diameter 12
i.e
Here R = R and R1 = 12/2 = 6
R = 14.696
=> D = X = 14.696 * 2 = 29.3938 cm.
v1=
v2=
% Increase in volume = (V2-V1) / (V2*100)
Let width = x
Then, height = 6x and length = 42x
42x * 6x * x = 16128
x = 4
Number of books that can be placed in the larger box is given by Volume of Box / Volume of book.
Now, n = 25 x 42 x 60 / 7 x 6 x 5
= 63000 / 210
= 300.
Therefore, 300 books can be in that box.
It takes four of those little squares -- each one 1/2 inch on a side -- to cover one square inch. That's because each one is 1/2 x 1/2, or 1/4 of a square inch.
In a rectangle that is 48 inches by 48 inches, there are 2304 square inches.(1 ft = 12 inches)
Since it takes 4 little squares to cover 1 sq inch, then it would need 2304 x 4 squares (1/2 inch on a side each) to cover a rectangle 4 feet by 4 feet.
That is 9,216 of those squares.
Vol of silver = = 66 C.C
Given D= 1mm => R = D/2 = 1/20 cm
=> = 66
= 66 x 400 x (7/22) = 8400 cm = 84 mtrs.
Since level of water increased in cylinder by height 4.
This is because of the rectangular block .
Therefore , area of rectangular block immersed in water is
=
Thats why portion of block immersed in water is
= (22/7 * 36 * 4) / total vol. of rectangle
= (22/7 * 36 * 4)/ (7*5*6)
= (22/7 * 24)/ 35.
Let the length of the wire be h.
Radius r =1/2 mm = 1/20 cm
=> h= (66 x 20 x 20) x (7/22) = 8400cm = 84m
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