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- Question
A rectangular box measures internally 1.6m long, 1m broad and 60cm deep. The number of cubical box each of edge 20cm that can be packed inside the box is:
Options- A. 30
- B. 60
- C. 90
- D. 120
- Correct Answer
- 120
ExplanationNumber of blocks = =120
- 1. A cylindrical rod of iron, whose height is equal to its radius, is melted and cast into spherical balls whose radius is half the radius of the rod. Find the number of balls.
Options- A. 3
- B. 4
- C. 5
- D. 6 Discuss
- 2. Water flows into a tank 200 m x 160 m through a rectangular pipe of 1.5m x 1.25 m @ 20 kmph . In what time (in minutes) will the water rise by 2 meters?
Options- A. 92min
- B. 93min
- C. 95min
- D. 96min Discuss
- 3. A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1cm when a man gets on it. The mass of the man is:
Options- A. 12 kg
- B. 60 kg
- C. 72 kg
- D. 96 kg Discuss
- 4. The areas of three consecutive faces of a cuboid are 12 cm², 20cm² and 15 cm², then the volume (in cm³) of the cuboid is
Options- A. 60
- B. 55
- C. 45
- D. 40 Discuss
- 5. How many iron rods, each of length 7 mts and diameter 2 cms can be made out of 0.88 cubic metre of iron ?
Options- A. 500
- B. 600
- C. 400
- D. 300 Discuss
- 6. The height of the wall is 6 times its width and lenght of the wall is 7 times its height .if the volume of the wall be 16128 cu.m.its width is
Options- A. 4m
- B. 5m
- C. 6m
- D. 7m Discuss
- 7. Which measurement unit represents volume?
Options- A. milliliter
- B. Cubic centimeter
- C. Meter cube
- D. All of the above Discuss
- 8. If the radius of base and height of a cone are increased by 10%, find the percentage of increase of its volume
Options- A. 33.5%
- B. 33.1%
- C. 32.1%
- D. 53.1% Discuss
- 9. A single pipe of diameter x has to be replaced by six pipes of diameters 12 cm each. The pipes are used to covey some liquid in a laboratory. If the speed/flow of the liquid is maintained the same then the value of x is ?
Options- A. 14.69 cm
- B. 29.39 cm
- C. 18.65 cm
- D. 22.21 cm Discuss
- 10. Find the ratio of the surfaces of the inscribed and circumscribed spheres about a cube.
Options- A. 1:2
- B. 1;3
- C. 1:4
- D. 1:5 Discuss
Volume and Surface Area problems
Search Results
Correct Answer: 6
Explanation:
Volume of rod = = =
Volume of one spherical ball =r/2
Volume of the spherical ball =
Number of balls=Volumeof rod/volumeof one ball
Correct Answer: 96min
Explanation:
Volume required in the tank = (200 x 150 x 2) cu.m = 60000 cu.m
Length of water column flown in1 min =(20 x 1000)/60 m =1000/3 m
Volume flown per minute = 1.5 x 1.25 x (1000/3) cu.m= 625 cu.m.
Required time = (60000/625)min = 96min
Correct Answer: 60 kg
Correct Answer: 60
Explanation:
From the given data,
let the length, breadth and height of the cuboid are m, n, r
m x n = 12
n x r = 20
r x m = 15
Hence, m x n x n x r x r x m = 12 x 20 x 15
mnr = sqrt of (12x20x15) = 60 cub.cm.
Correct Answer: 400
Explanation:
Given length of iron rod =7 mts and and diameter of rod = 2 cms
=> r = 1/100 mts
Therefore, Volume of one rod = cu. m = cu. m = cu. m
Given volume of iron = 0.88 cu. m
Therefore, Number of rods = = 400.
Correct Answer: 4m
Explanation:
Let width = x
Then, height = 6x and length = 42x
42x * 6x * x = 16128
x = 4
Correct Answer: All of the above
Correct Answer: 33.1%
Explanation:
v1=
v2=
% Increase in volume = (V2-V1) / (V2*100)
Correct Answer: 29.39 cm
Explanation:
Volume of water flowing through 1 pipe of diameter x = Volume discharged by 6 pipes of diameter 12 cms.
As speed is same, area of cross sections should be same.
Area of bigger pipe of diameter x = Total area of 6 smaller pipes of diameter 12
i.e
Here R = R and R1 = 12/2 = 6
R = 14.696
=> D = X = 14.696 * 2 = 29.3938 cm.
Correct Answer: 1:2
Explanation:
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