Discussion
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- Question
There is a cylinder circumscribing the hemisphere such that their bases are common. Find the ratio of their volumes
Options- A. 3/2
- B. 5/2
- C. 7/2
- D. 9/2
- Correct Answer
- 3/2
ExplanationR =OA = OB = Radius of hemisphere.
= Radius of cylinder ABCD.
Height of the cylinder = BC = radiusVolume of cylinder/Volume of hemisphere =
- 1. Find the surface area of a cuboid 16 m long, 14 m broad and 7 m high
Options- A. 868 sq.cm
- B. 920 sq.cm
- C. 727 sq.cm
- D. 900 sq.cm Discuss
- 2. A large cube is formed from the material obtained by melting three smaller cubes of 3, 4 and 5 cm side. What is the ratio of the total surface areas of the smaller cubes and the large cube?
Options- A. 2 : 1
- B. 3 : 2
- C. 25 : 18
- D. 27 : 20 Discuss
- 3. A cuboidal block 6cm x 9cm x 12cm is cut up into an exact number of equal cubes.The least possible number of equal cubes will be
Options- A. 6
- B. 9
- C. 24
- D. 30 Discuss
- 4. Ratio between heights of two cylinder in the ratio 3:5. Their volumes are in the ratio 27:80. Find ratio between their radius ?
Options- A. 1:3
- B. 2:1
- C. 3:4
- D. 4:7 Discuss
- 5. The circumferences of two circles are 264 meters and 352 meters. Find the difference between the areas of the larger and the smaller circles ?
Options- A. 2413 sq.m
- B. 1234 sq.m
- C. 4312 sq.m
- D. 2143 sq.m Discuss
- 6. The capacity of a tank of dimensions (8m x 6m x 2.5m)is
Options- A. 120 litres
- B. 1200 litres
- C. 12000 litres
- D. 120000 litres Discuss
- 7. How many iron rods, each of length 7 mts and diameter 2 cms can be made out of 0.88 cubic metre of iron ?
Options- A. 500
- B. 600
- C. 400
- D. 300 Discuss
- 8. The areas of three consecutive faces of a cuboid are 12 cm², 20cm² and 15 cm², then the volume (in cm³) of the cuboid is
Options- A. 60
- B. 55
- C. 45
- D. 40 Discuss
- 9. A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1cm when a man gets on it. The mass of the man is:
Options- A. 12 kg
- B. 60 kg
- C. 72 kg
- D. 96 kg Discuss
- 10. Water flows into a tank 200 m x 160 m through a rectangular pipe of 1.5m x 1.25 m @ 20 kmph . In what time (in minutes) will the water rise by 2 meters?
Options- A. 92min
- B. 93min
- C. 95min
- D. 96min Discuss
Volume and Surface Area problems
Search Results
Correct Answer: 868 sq.cm
Explanation:
Surface area = [2 (16 x 14 + 14 x 7 + 16 x 7)] sq.cm
= (2 x 434)sq.cm = 868 sq.cm
Correct Answer: 25 : 18
Explanation:
Volume of the large cube = = 216 cu.cm.
Let the edge of the large cube be a.
So, = 216
=>a = 6 cm.
Required ratio =
Correct Answer: 24
Explanation:
Volume of block=(6 x 9 x 12) cu.cm = 648 cu.cm
Side of largest cube = H.C.F of 6,9,12 = 3cm
Volume of the cube=(3 x 3 x 3)=27cu.cm
Number of cubes=(648/27)=24
Correct Answer: 3:4
Correct Answer: 4312 sq.m
Explanation:
Let the radii of the smaller and the larger circles be 's' m and 'l' m respectively.
= 264 and = 352
s = and l =
Difference between the areas =
=
=
= (176 - 132)(176 + 132) /
= (44 x 308) / (22/7) = 4312 sq.m
Correct Answer: 120000 litres
Explanation:
capacity of a tank = volume of tank
= [ (8 x 100) x (6 x 100) x (2.5 x 100) ]/ 1000 litres
= 120000 litres
Correct Answer: 400
Explanation:
Given length of iron rod =7 mts and and diameter of rod = 2 cms
=> r = 1/100 mts
Therefore, Volume of one rod = cu. m = cu. m = cu. m
Given volume of iron = 0.88 cu. m
Therefore, Number of rods = = 400.
Correct Answer: 60
Explanation:
From the given data,
let the length, breadth and height of the cuboid are m, n, r
m x n = 12
n x r = 20
r x m = 15
Hence, m x n x n x r x r x m = 12 x 20 x 15
mnr = sqrt of (12x20x15) = 60 cub.cm.
Correct Answer: 60 kg
Correct Answer: 96min
Explanation:
Volume required in the tank = (200 x 150 x 2) cu.m = 60000 cu.m
Length of water column flown in1 min =(20 x 1000)/60 m =1000/3 m
Volume flown per minute = 1.5 x 1.25 x (1000/3) cu.m= 625 cu.m.
Required time = (60000/625)min = 96min
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