Simple Interest on Rs. (260-20) for a gven time= Rs.20
Simple Interest on Rs. (260-20) for a half time = Rs.10
True Discount on Rs.250 = Rs.10
True Discount on Rs.260 = Rs.[(10/250) x 260] = Rs. 10.40
loss = C.P - S.P = 490 - 465.50 =24.50
loss % = (loss x 100)/C.P = (24.50 x 100)/490 = 5%
We know that,
P.W = 100×T.D/R×T
= 100×168/14×2
P.W = 600.
Now, required Sum = (P.W. + T.D.)
= Rs. (600 + 168)
= Rs. 768.
PW =
P.W= Amount ? (T.D)
Time =
Let amount be Rs. x.
Then, [X * R * T] / [100+(R * T)]
x= Rs.6540
Amount = Rs. 6540.
P.W. = Rs. (6540 ? 540) =Rs. 6000.
Let the sum be Rs. x. Then,
(x/2)+(2x/5)-(8x/9) = 40
x=3600.
Therfore, amount of bill=Rs. 3600.
P.W = Rs. (1760 - 160) = Rs.1600
S.I on Rs.1600 at 12% is Rs. 160
Time = (100 x 160)/(1600 x 12) = 5/6 years = (5/6) x 12 months = 10 months
S.I on Rs.750= T.D on Rs. 960
This means P.W of Rs. 960 due 2 years hence is Rs.750
Therefore , T.D= Rs. (960 - 750) = Rs. 210
Thus, S.I on Rs. 750 for 2 years is Rs. 210
Rate =[ (100 x 210) / (750 x 2) ] % = 14%
A has to pay = Present worth of Rs220 due 1yr hence
= Rs.[(220 x 100)/100+(10 x 1)] = Rs.200
A actually pays = Rs.110+PW of Rs.110 due 2 yrs hence
= [110+(110 x 100)] / [100+(10 x 2)] = Rs.192.66
So, A gains Rs. (200-192.66) = Rs.7.34
Sum ? Amount
A = (SI x TD)/(SI - TD)
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