P.W= Amount ? (T.D)
Time =
Let amount be Rs. x.
Then, [X * R * T] / [100+(R * T)]
x= Rs.6540
Amount = Rs. 6540.
P.W. = Rs. (6540 ? 540) =Rs. 6000.
Present worth = Amount - True Discount = 110 -10 = Rs.100
SI on Rs.100 for a certain time = Rs.10
SI on Rs.100 for doube the time = Rs.20
True Discount on Rs.120 = 120 - 100 = Rs.20
True Discount on Rs.110 = = Rs.18.33
PW =
PW of Rs.12,880 due 8 months hence
= Rs. [12880 x 100] / [100+(18 x 8/12)] =Rs.11500
Clearly 12000 in cash is a better offer.
Required Sum = PW of Rs.702 due 6 months hence + PW of Rs.702 due 1 year hence
= Rs.[ (100 x 702) / (100+(8 x 1/2)) ] + [ (100 x 702) / (100+(8 x 1)) ]
= Rs.1325
PW =
We know that,
P.W = 100×T.D/R×T
= 100×168/14×2
P.W = 600.
Now, required Sum = (P.W. + T.D.)
= Rs. (600 + 168)
= Rs. 768.
loss = C.P - S.P = 490 - 465.50 =24.50
loss % = (loss x 100)/C.P = (24.50 x 100)/490 = 5%
Simple Interest on Rs. (260-20) for a gven time= Rs.20
Simple Interest on Rs. (260-20) for a half time = Rs.10
True Discount on Rs.250 = Rs.10
True Discount on Rs.260 = Rs.[(10/250) x 260] = Rs. 10.40
Let the sum be Rs. x. Then,
(x/2)+(2x/5)-(8x/9) = 40
x=3600.
Therfore, amount of bill=Rs. 3600.
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.