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- Question
48 people could complete a task in 17 days. After 6 days, 4 of the workers left. How many days from then will it take to complete the task?
Options- A. 12
- B. 13
- C. 15
- D. 16
- Correct Answer
- 12
ExplanationGiven, 48 people can do a work in 17 days. So total work = 48 x 17 = 816
Work done by 48 people in 6 days = 288.The remaining work = 816 - 288 = 528
After 6 days four workers left. So number of people working is 44
Total number of days required for 44 men to complete the remaining work = 528/44 = 12 - 1. A takes 24 day in completing a work alone. Time taken by A in completing 1/3rd of the work is equal to the time taken by B in completing half of the work. How many days will be taken in completing the work if both A & B start working together?
Options- A. 21/3 days
- B. 48 days
- C. 40 days
- D. 48/5 days Discuss
- 2. Prabhat has done 1/2 of a job in 12 days. Santosh completes the rest of the job in 6 days. In how many days can they together do the job?
Options- A. 12 days
- B. 4 days
- C. 8 days
- D. 16 days Discuss
- 3. A can do a work in 24 days. B is 20% more efficient than A. If C can do the work in 10 more days than B, find the time taken by A and C together to complete the work.
Options- A. 43/3 days
- B. 40/3 days
- C. 50/3 days
- D. 41/2 days Discuss
- 4. Type 1 workers can do three times the work of Type 2 workers. Twelve Type 1 workers can complete a task in 10 days. How many days would it have taken 4 Type 1 and 8 Type 2 workers to complete the same task?
Options- A. 16
- B. 17
- C. 20
- D. 18 Discuss
- 5. A is 50% more efficient than B. They together start the work and 7/12th of work is left after 8 days. Find in what time B alone will complete the whole work.
Options- A. 36 days
- B. 44 days
- C. 50 days
- D. 40 days Discuss
- 6. Two typists of varying skills can do a typing jobin6 minutesifthey work together.Ifthe first typist typed alone for 4 minutes and then the second typist typed alone for 6 minutes, they would be left with 1/5 of the whole work.Howmany minutes would it take the slower typist to complete the typing job working alone?
Options- A. 10 minutes
- B. 15 minutes
- C. 12 minutes
- D. 20 minutes Discuss
- 7. X can do a piece of work in 'p' days and Y can do the same work in 'q' days . Then the number of days in which X and Y can together do that work is
Options- A. p+q2
- B. 1p+1q
- C. pqp+q
- D. Pq Discuss
- 8. A piece of work was finished by A, B and C together. A and B together finished 60% of the work and B and C together finished 70% of the work. Who among the three is most efficient?
Options- A. A
- B. B
- C. C
- D. None Discuss
- 9. If Data Interpretation and Modern Maths were taught for a combined time of 96 hours, then for how much time (in hours) were Number system and Geometry taught?
Options- A. 136
- B. 184
- C. 216
- D. 232 Discuss
- 10. One tap can fill a water tank in 50 mins and another tap can make the filled tank empty in 75 mins. If both the taps are open together, already half filled tank would be full in
Options- A. 60 min
- B. 75 min
- C. 125 min
- D. 150 min Discuss
Time and Work problems
Search Results
Correct Answer: 48/5 days
Explanation:
Ans.
Time taken by A to complete a work alone - 24 days
Time taken by A in completing 1/3 of work = 24*1/3= 8 Days
8 day = time taken by B in completing 1/2 of work
B alone can complete the work = 16 days
The required time in completing the work if both A & B start working together?
16*24 / 40 = 48/5 Days
Correct Answer: 8 days
Correct Answer: 40/3 days
Explanation:
A takes 24 days to complete a work.
B is 20% more efficient than A,
hence B will take (24*100)/120 = 20 days.
C takes (20+10) = 30 days.
Time taken by A & C in completing the work = (24*30)/(24+30) = (24*30)/54 = 40/3 days.
Correct Answer: 18
Correct Answer:
Explanation:
Ratio of efficiency of A to B is 3 : 2
Let, In 8 days they complete = (3 + 2) × 8 = 40 units
So, total work = 40 × 12/5 units
Time taken by B alone to complete whole work = 40 × 12/5 ×2 = 48 days
Correct Answer: 15 minutes
Explanation:
Working efficiency of both typist together = 100/6 = 16.66%
Let the efficiency of first typist be x and second typist be (16.66 ?x)
First typist for 4 minute + second tyoistfor 6 minute = 80% work
?4x + (16.66 ?x) X 6 = 80%
?4x + 100% -6x = 80%,
?x = 10%
First typist typed 10% per minute, second typst typed (16.66 ?10) = 6.66% per minute
Slowest is second typist complete whole job in 100/6.66 = 15.01 = 15 minute
Correct Answer: pqp+q
Correct Answer: C
Correct Answer: 232
Correct Answer: 75 min
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