A takes 24 days to complete a work.
B is 20% more efficient than A,
hence B will take (24*100)/120 = 20 days.
C takes (20+10) = 30 days.
Time taken by A & C in completing the work = (24*30)/(24+30) = (24*30)/54 = 40/3 days.
Ratio of efficiency of A to B is 3 : 2
Let, In 8 days they complete = (3 + 2) × 8 = 40 units
So, total work = 40 × 12/5 units
Time taken by B alone to complete whole work = 40 × 12/5 ×2 = 48 days
Time required will be in ratio = 5:4
B alone will do it in =16 days
Ans.
Time taken by A to complete a work alone - 24 days
Time taken by A in completing 1/3 of work = 24*1/3= 8 Days
8 day = time taken by B in completing 1/2 of work
B alone can complete the work = 16 days
The required time in completing the work if both A & B start working together?
16*24 / 40 = 48/5 Days
Given, 48 people can do a work in 17 days. So total work = 48 x 17 = 816
Work done by 48 people in 6 days = 288.
The remaining work = 816 - 288 = 528
After 6 days four workers left. So number of people working is 44
Total number of days required for 44 men to complete the remaining work = 528/44 = 12
Working efficiency of both typist together = 100/6 = 16.66%
Let the efficiency of first typist be x and second typist be (16.66 ?x)
First typist for 4 minute + second tyoistfor 6 minute = 80% work
?4x + (16.66 ?x) X 6 = 80%
?4x + 100% -6x = 80%,
?x = 10%
First typist typed 10% per minute, second typst typed (16.66 ?10) = 6.66% per minute
Slowest is second typist complete whole job in 100/6.66 = 15.01 = 15 minute
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