1 boy's 1 day work = 1/70
1 girl's 1 day work = 1/140
(5 boys + 10 girls)'s 1 day work = (5/70 + 10/140) = (1/14 + 1/14) = 1/7
5 boys and 10 girls will complete the work in 7 days.
Let A worked for x days.
x/21 + 4/28 = 1 => x = 18
A worked for 18 days. So, A can complete the remaining work in 18 - 4 = 14 days.
2 engines of former type for one hour consumes (2 x 24)/(6 x8) = 1 metric ton
i.e. 3 engines of latter type consumes 1 ton for one hour
Hence 9 engines consumes 3 tons for one hour
For 15 hours it is 15 x 3 = 45 metric tonnes.
Quantity of food = 200 X 31 = 6200 man-days
Till 27 days, quantity consumed = 27 X 200 = 5400 man-days
Remaining quantity = 6200 ?5400 = 800 man days
Remaining soilders = 200 ?120 = 80
Let remaining food will be sufficient for x days?5400 + 80x = 6200?x= 10 days
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