2 engines of former type for one hour consumes (2 x 24)/(6 x8) = 1 metric ton
i.e. 3 engines of latter type consumes 1 ton for one hour
Hence 9 engines consumes 3 tons for one hour
For 15 hours it is 15 x 3 = 45 metric tonnes.
Let A worked for x days.
x/21 + 4/28 = 1 => x = 18
A worked for 18 days. So, A can complete the remaining work in 18 - 4 = 14 days.
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