It is given that efficiency ratio =3:1
so time ratio will be 1:3 (since work is same)
Also given that time diff = 32 days. ratio difference = 3-1 =2
2 ratio = 32 days
1 ratio = 16 days.
So A will alone finish it in 16 days and B will finish it in 16*3 = 48 days.
Total work = LCM of 16 and 48 = 48.
Total time = Total work/Total efficiency
ie; 48/4= 12 days.
47/10000 = .0047
.02 =(2/100) x 100% =2%
Let N / 11 = 233
Then, N = 233 x 11 = 2563
? Missing digit is 5.
121012 = 12 x 10084 + 4
? remainder = 4
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
Subtract 20, 25, 30, 35, 40, 45 from successive numbers. So 0 is wrong.
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