(A+B)'s 15 days work =
Remaining work = 1/4
Now, 1/4 work is done by A in 10 days.
Whole work will be done by A in (10 x 4) = 40 days.
Work done by P alone in one day = 1/6th of the total work done by Q alone in one day = 1/3(of that done by P in one day) = 1/3(1/6 of the total) = 1/18 of the total.
Work done by P and Q, working together in one day = 1/6 + 1/18 = 4/18 = 2/9
They would take 9/2 days = 4 (1/2) days to complete the work working together.
From the above formula i.e (m1 x t1/w1) = (m2 x t2/w2)
so, [(34 x 8 x 9)/(2/5)] = [(M x 6 x 9)/(3/5)]
so, M = 136 men
Number of men to be added to finish the work = 136-34 = 102 men.
(45 x 9)/40 = (M x 7)/56 => M = 81
=> 81 ? 45 = 36
5M + 2B = 4(1M + 1B)
5M + 2B = 4M + 4B
1M = 2B
The required ratio of work done by a man and a boy = 2:1
(10 * 6) women can complete the work in 1 day.
Therefore, 1 woman's 1 day's work = 1/60
(6 * 5) men can complete the work in 1 day.
Therefore, 1 man's 1 day's work = 1/30
so, required ratio =1/30 : 1/60 = 2:1
Let the total number of documents to be printed be 12.
The number of documents printed by P in 1 day = 4.
The number of documents printed by Q in 1 day = 3.
The number of documents printed by R in 1 day = 2.
Thus, the total number of documents that can be printed by all the machines working simultaneously in a single day = 9.
Therefore, the number of days taken to complete the whole work = 12/9 = 4/3 days.
A can write in 1hour = 32/6 pages
Similarly, B in 1 hour = 40/5 pages
Together (A+B) in 1 hour = 32/6 + 40/5 = 40/3
So, A+B write 40/3 pages in 1 hour
A+B write 110 pages in (3/40) x 110 Hours = 8 hours 15 min.
A can complete the work in 12 days working 8 hours a day
=> Number of hours A can complete the work = 12×8 = 96 hours
=> Work done by A in 1 hour = 1/96
B can complete the work in 8 days working 10 hours a day
=> Number of hours B can complete the work = 8×10 = 80 hours
=> Work done by B in 1 hour = 1/80
Work done by A and B in 1 hour = 1/96 + 1/80 = 11/480
=> A and B can complete the work in 480/11 hours
A and B works 8 hours a day.
Hence total days to complete the work with A and B working together
= (480/11)/ (8) = 60/11 days
Suppose A, B and C take x, x/2 and x/3 respectively to finish the work.
Then, (1/x + 2/x + 3/x) = 1/2
6/x = 1/2 => x = 12
So, B takes 6 hours to finish the work.
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