After day 1, A finishes 1/9 of the work.
After day 2, B finishes 1/7 more of the total work. (1/9) + (1/7) is finished.
After day 3, C finishes 1/5 more of total work. Total finished is 143/315.
So, after day 6, total work finished is 286/315.
Now remaining work = 29 /315
On day 7, A will work again
Work will be completed on day 7 when A is working. He must finish 29/315 of total remaining work.
Since he takes 9 days to finish the total task, he will need 261/315 of the day.
Total days required is 6 + (261/315) days.
Let the 1 day work of a boy=b and a girl=g, then
2b + g = 1/5 ---(i) and
b + 2g = 1/6 ---(ii)
On solving (i) & (ii), b=7/90, g=2/45
As payment of work will be in proportion to capacity of work and a boy is paid $ 28/week,
so a girl will be paid
= 16 $.
we know that m1 x d1 = m2 x d2
=> 4 x 6 = 5 x d
where d = no. of days taken by 5 men to paint
d = 24/5 days.
L's 10 days work =
Remaining work =
Now, work is done by K in one day = 1/18
1/3 work is done by K in = 6 days
T C B
16 10 15
8 12 12
128 120 180 <------- in one hour
1280 1200 1800 <------- in 10 hours
Since, restriction is imposed by composers i.e,since only 1200 books can be composed i 10 hours so not more than 1200 books can be finally pepared.
Let there are L men
job requires LK man hours.
job completed in first 4 hrs = L x 4 = 4L
job completed in next 4 hrs = 4 x L/2 = 2L
job completed in next 4 hrs = 4 x L/4 = L
job completed in last 4 hrs = 4 x L/8 = L/2
4L + 2L + L + L/2 = KL
K = 7+1/2 = 7.5 hours.
1/15 + 1/12 + 1/R = 1/6, we got R = 60 (it means R will take 60 days to complete the work alone)
so ratio of work done by P:Q:R = 1/15 : 1/12 : 1/60 = 5 : 4 : 1
so R share = (1/10) x 1200 = 120.
5M + 2B = 4(1M + 1B)
5M + 2B = 4M + 4B
1M = 2B
The required ratio of work done by a man and a boy = 2:1
(45 x 9)/40 = (M x 7)/56 => M = 81
=> 81 ? 45 = 36
From the above formula i.e (m1 x t1/w1) = (m2 x t2/w2)
so, [(34 x 8 x 9)/(2/5)] = [(M x 6 x 9)/(3/5)]
so, M = 136 men
Number of men to be added to finish the work = 136-34 = 102 men.
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