After day 1, A finishes 1/9 of the work.
After day 2, B finishes 1/7 more of the total work. (1/9) + (1/7) is finished.
After day 3, C finishes 1/5 more of total work. Total finished is 143/315.
So, after day 6, total work finished is 286/315.
Now remaining work = 29 /315
On day 7, A will work again
Work will be completed on day 7 when A is working. He must finish 29/315 of total remaining work.
Since he takes 9 days to finish the total task, he will need 261/315 of the day.
Total days required is 6 + (261/315) days.
47/10000 = .0047
.02 =(2/100) x 100% =2%
Let N / 11 = 233
Then, N = 233 x 11 = 2563
? Missing digit is 5.
121012 = 12 x 10084 + 4
? remainder = 4
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
Subtract 20, 25, 30, 35, 40, 45 from successive numbers. So 0 is wrong.
Comments
There are no comments.Copyright ©CuriousTab. All rights reserved.