Let the 1 day work of a boy=b and a girl=g, then
2b + g = 1/5 ---(i) and
b + 2g = 1/6 ---(ii)
On solving (i) & (ii), b=7/90, g=2/45
As payment of work will be in proportion to capacity of work and a boy is paid $ 28/week,
so a girl will be paid
= 16 $.
we know that m1 x d1 = m2 x d2
=> 4 x 6 = 5 x d
where d = no. of days taken by 5 men to paint
d = 24/5 days.
L's 10 days work =
Remaining work =
Now, work is done by K in one day = 1/18
1/3 work is done by K in = 6 days
T C B
16 10 15
8 12 12
128 120 180 <------- in one hour
1280 1200 1800 <------- in 10 hours
Since, restriction is imposed by composers i.e,since only 1200 books can be composed i 10 hours so not more than 1200 books can be finally pepared.
Let number of days Charan can do the same work alone is 'd' days.
According to the given data,
Therefore, Charan alone can complete the work in 96 days.
After day 1, A finishes 1/9 of the work.
After day 2, B finishes 1/7 more of the total work. (1/9) + (1/7) is finished.
After day 3, C finishes 1/5 more of total work. Total finished is 143/315.
So, after day 6, total work finished is 286/315.
Now remaining work = 29 /315
On day 7, A will work again
Work will be completed on day 7 when A is working. He must finish 29/315 of total remaining work.
Since he takes 9 days to finish the total task, he will need 261/315 of the day.
Total days required is 6 + (261/315) days.
Let there are L men
job requires LK man hours.
job completed in first 4 hrs = L x 4 = 4L
job completed in next 4 hrs = 4 x L/2 = 2L
job completed in next 4 hrs = 4 x L/4 = L
job completed in last 4 hrs = 4 x L/8 = L/2
4L + 2L + L + L/2 = KL
K = 7+1/2 = 7.5 hours.
1/15 + 1/12 + 1/R = 1/6, we got R = 60 (it means R will take 60 days to complete the work alone)
so ratio of work done by P:Q:R = 1/15 : 1/12 : 1/60 = 5 : 4 : 1
so R share = (1/10) x 1200 = 120.
5M + 2B = 4(1M + 1B)
5M + 2B = 4M + 4B
1M = 2B
The required ratio of work done by a man and a boy = 2:1
(45 x 9)/40 = (M x 7)/56 => M = 81
=> 81 ? 45 = 36
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