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- Question
Sharan and Mayukh, working together, can complete a task in 18 days. However, Mayukh works alone and leaves after completing 1/3 of the task. Then, Sharan takes over and completees the remaining work by himself. As a result, the duo could complete the task in 40 days. How many days would Sharan alone have taken to do the job if Mayuk' had worked faster than Sharan ?
Options- A. 24
- B. 45
- C. 72
- D. 30
- Correct Answer
- 45
- 1. Lasya alone can do a work in 16 days. Srimukhi?s efficiency is 20 % lesser than that of Laya. If Rashmi and Srimukhi together can do the same work in 12 days, then find the efficiency ratio of Rashmi to that of Lasya?
Options- A. 19 : 7
- B. 30 : 19
- C. 8 : 15
- D. 31 : 17 Discuss
- 2. A, B and C can do a piece of work in 72, 48 and 36 days respectively. For first p/2 days, A & B work together and for next ((p+6))/3days all three worked together. Remaining 125/3% of work is completed by D in 10 days. If C & D worked together for p day then, what portion of work will be remained?
Options- A. 1/5
- B. 1/6
- C. 1/7
- D. 1/8 Discuss
- 3. Amar can do a piece of work in 10 days. He works at it for 4 days and then Arun finishes it in 9 days. In how many days can Amar and Arun together finish the work ?
Options- A. 4 days
- B. 8 days
- C. 3 days
- D. 6 days Discuss
- 4. Five men and nine women can do a piece of work in 10 days. Six men and twelve women can do the same work in 8 days. In how many days can three men and three women do the work ?
Options- A. 18 days
- B. 20 days
- C. 16 days
- D. 14 days Discuss
- 5. K can build a wall in 30 days. L can demolish that wall in 60 days. If K and L work on alternate days, when will the wall be completed ?
Options- A. 120 days
- B. 119 days
- C. 118 days
- D. 117 days Discuss
- 6. The ratio of efficiencies of P, Q and R is 2 : 3 : 4. While P and R work on alternate days and Q work for all days. Now the work completed in total 10 days and the total amount they get is Rs. 1200. Find the amount of each person(respectively).
Options- A. 200, 600, 400
- B. 400, 600, 200
- C. 600, 200, 400
- D. 400, 200, 600 Discuss
- 7. A town having teenagers(boys & girls) of 5000 requires 150 litre of water per head. It has a tank measuring 20 m × 15 m × 5 m. The water of this tank will sufficient for ____ days.
Options- A. 8
- B. 6
- C. 4
- D. 2 Discuss
- 8. Mr. stenley employed a certain number of typist for his project. 8 days later 20% of the typist left the job and it was found that it took as much time to complete the rest work from then as the entire work needed with all the employed typists. The average speed of a typist is 20 pages/hour. Minimum how many typist could be employed?
Options- A. 10
- B. 5
- C. 15
- D. 4 Discuss
- 9. 5 men and 3 boys can together cultivate a 23 acre field in 4 days and 3 men and 2 boys together can cultivate a 7 acre field in 2 days. How many boys will be needed together with 7 men, if they cultivate 45 acre of field in 6 days.
Options- A. 6
- B. 4
- C. 2
- D. 3 Discuss
- 10. Raghu can complete a work in 12days working 9 hours a day. Arun can complete the same work in 8 days working 11 hours a day. If both Raghu and Arun work together, working 12 hours a day, in how many days can they complete the work ? A) 3449 days B) 12449 days C) 4349 days D) 41249 days
Options- A. Option A
- B. Option B
- C. Option C
- D. Option D Discuss
Time and Work problems
Search Results
Correct Answer: 8 : 15
Explanation:
Given Lasya can do a work in 16 days.
Time taken by Rashmi = n days
=> (12 x 20)/(20 - 12) = (12 x 20)/n
=> n= 30 days.
Required ratio of efficiencies of Rashmi and Lasya = 1/30 :: 1/16 = 8 : 15.
Correct Answer: 1/6
Explanation:
Total work is given by L.C.M of 72, 48, 36
Total work = 144 units
Efficieny of A = 144/72 = 2 units/day
Efficieny of B = 144/48 = 3 units/day
Efficieny of C = 144/36 = 4 units/day
According to the given data,
2 x p/2 + 3 x p/2 + 2 x (p+6)/3 + 3 x (p+6)/3 + 4 x (p+6)/3 = 144 x (100 - 125/3) x 1/100
3p + 4.5p + 2p + 3p + 4p = 84 x 3 - 54
p = 198/16.5
p = 12 days.
Now, efficency of D = (144 x 125/3 x 1/100)/10 = 6 unit/day
(C+D) in p days = (4 + 6) x 12 = 120 unit
Remained part of work = (144-120)/144 = 1/6.
Correct Answer: 6 days
Explanation:
4/10 + 9/x = 1 => x = 15
Then both can do in
1/10 + 1/15 = 1/6 => 6 days
Correct Answer: 20 days
Explanation:
(5m + 9w)10 = (6m + 12w)8
=> 50m + 90w = 48w + 96 w => 1m = 3w
5m + 9w = 5m + 3m = 8m
8 men can do the work in 10 days.
3m +3w = 3m + 1w = 4m
So, 4 men can do the work in (10 x 8)/4 = 20 days.
Correct Answer: 117 days
Explanation:
K's work in a day(1st day) = 1/30
L's work in a day(2nd day)= -1/60(demolishing)
hence in 2 days, combined work= 1/30 - 1/60 =1/60
since both works alternatively, K will work in odd days and L will work in even days.
1/60 unit work is done in 2 days
58/60 unit work will be done in 2 x 58 days = 116 days
Remaining work = 1-58/60 = 1/30
Next day, it will be K's turn and K will finish the remaining 1/30 work.
hence total days = 116 + 1 = 117.
Correct Answer: 200, 600, 400
Explanation:
Ratio of efficiencies of P, Q and R = 2 : 3 : 4
From the given data,
Number of working days of P, Q, R = 5 : 10 : 5
Hence, ratio of amount of p, Q, R = 2x5 : 3x10 : 4x5 = 10 : 30 : 20
Amounts of P, Q, R = 200, 600 and 400.
Correct Answer: 2
Explanation:
Total Water reqduired = 5000 × 150 lit = 750,000 litres = 750 cu.m.
Volume of tank = 20 × 15 × 5 = 1500 Cu.m.
Number of days required =1500/750 = 2 days.
Correct Answer: 5
Explanation:
Since 20% i.e 1/5 typists left the job. So, there can be any value which is multiple of 5 i.e, whose 20% is always an integer. Hence, 5 is the least possible value.
Correct Answer: 2
Explanation:
Let work done by 1 man in i day be m
and Let work done by 1 boy in 1 day be b
From the given data,
4(5m + 3b) = 23
20m + 12b = 23....(1)
2(3m + 2b) = 7
6m + 4b = 7 ....(2)
By solving (1) & (2), we get
m = 1, b = 1/4
Let the number of required boys = n
6(7 1 + n x 1/4) = 45
=> n = 2.
Correct Answer: Option C
Explanation:
Raghu can complete the work in (12 x 9)hrs = 108 hrs.
Arun can complete the work in (8 x 11)hrs = 88 hrs.
Raghu's 1 hrs work = 1/108 and Arun's 1 hrs work = 1/88
(Raghu + Arun)'s 1 hrs work =
So, both Raghu and Arun will finish the work in
Number of days of 12 hours each= =
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