From the given data,
Day Capacity
A -> 12 2
B -> 8 3 2
A + B + C -> 2 12
=> Capacity of C = 12 - 5 = 7
Ratio of capacity of A : B : C = 2 : 3 : 7
Difference of wages of C & B = 4/5 x 1540
= 4 x 308 = Rs. 1232
Now, Total work = LCM(16, 8) = 48
A's one day work = + 48/16 = + 3
B's one day work = - 48/8 = -6
Given A worked for 5 days to build the wall => 5 days work = 5 x 3 = + 15
2days B joined with A in working = 2(3 - 6) = - 6
Remaining Work of building wall = 48 - (15 - 6) = 39
Now this remaining work will be done by A in = 39/3 = 13 days.
Total work = 100+50 = 150man-days
In 8 days 100 man-days work has been completed. Now on 9th and 10th day there will be 25 workers. So in 2 days they wll complete additional 50 man- days work. Thus the work requires 2 more days.
Given that three athletes can complete one round around a circular field in 16, 24 and 36 min respectively.
Now, required time after which they met for the first time = LCM of (16, 24 & 36) min
Now, LCM of 16, 24, 36 = 144 minutes = 2 hrs 24 min.
Days remaining 124 ? 64 = 60 days
Remaining work = 1 - 2/3 = 1/3
Let men required men for working remaining days be 'm'
So men required = (120 x 64)/2 = (m x 60)/1 => m = 64
Men discharge = 120 ? 64 = 56 men.
9M + 12B ----- 12 days ...........(1)
12M + 12B ------- 10 days........(2)
10M + 10B -------?
108M + 144B = 120M +120B
24B = 12M => 1M = 2B............(3)
From (1) & (3)
18B + 12B = 30B ---- 12 days
20B + 10B = 30B -----? => 12 days.
We know that Time is inversely proportional to Efficiency
Here given time ratio of P & P+Q as
P/P+Q = 150/100 = 3:2
Efficiency ratio of P & Q as
P:Q = 2:1 ....(1)
Given Efficiency ratio of Q & R as
Q:R = 3:1 ....(2)
From (1) & (2), we get
P:Q:R = 6:3:1
P alone can finish the work in
22.5(3+1)/6 = 15 days.
Let Q complete that work in 'L' days
=>
=>
L = 25 days.
Given X can do in 10 days
=> 1 day work of X = 1/10
Y can do in 15 days
=> 1 day work of Y = 1/15
1day work of (X + Y) = 1/10 + 1/15 = 1/6
Given they are hired for 5 days
=> 5 days work of (X + Y) = 5 x 1/6 = 5/6
Therefore, Unfinished work = 1 - 5/6 = 1/6
Given (3 Men + 4 Women + 6 Children) -----> 9 days
But W = 2M and C = M/2
Now, convert Men and Children into Women by
Therefore, 7 women alone can complete this work in 9 days.
Remaining work = 1 - 9/10 = 1/10
=> A & B together completes 1/10 of work in 4 days
=> 1 work can completed in ------ ? days
Let it be x days
=>
=> x = 40 days.
Hence, A & B together can complete the work in 40 days.
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