Now, Total work = LCM(16, 8) = 48
A's one day work = + 48/16 = + 3
B's one day work = - 48/8 = -6
Given A worked for 5 days to build the wall => 5 days work = 5 x 3 = + 15
2days B joined with A in working = 2(3 - 6) = - 6
Remaining Work of building wall = 48 - (15 - 6) = 39
Now this remaining work will be done by A in = 39/3 = 13 days.
.02 =(2/100) x 100% =2%
Let N / 11 = 233
Then, N = 233 x 11 = 2563
? Missing digit is 5.
121012 = 12 x 10084 + 4
? remainder = 4
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
Subtract 20, 25, 30, 35, 40, 45 from successive numbers. So 0 is wrong.
NA
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