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- Question
6 men can complete a piece of work in 12 days. 8 women can complete the same piece of work in 18 days whereas 18 children can complete the piece of work in 10 days. 4 men, 12 women and 20 children work together for 2 days. If only men were to complete the remaining work in 1 day how many men would be required totally?
Options- A. 38
- B. 72
- C. 36
- D. 76
- Correct Answer
- 36
ExplanationGiven 4men, 12 women and 20 children work for 2 days.
Workdone for 2 days by 4men, 12 women and 20 children =
Therefore, remaining work = 1 - =
To complete the same work by only men in 1 day,
We know that M1 x D1 = M2 x D2
Here M1 = 6 , D1 = 12 and M2 = M , D2 = 1
12 x 6 = M x 1
=> M = 12 x 6 = 72
=> But the remaining work = 1/2
Men required => 1/2 x 72 = 36
Only men required to Complete the remaining work in 1 day = 36.
- 1. If 10 men take 15 days to complete a work. In how many days will 37 men complete the work?
Options- A. 3 days
- B. 4 days
- C. 5 days
- D. 6 days Discuss
- 2. After working for 8 days, Arun finds that only 13 rd of the work has been done. He employs Akhil who is 60% as efficient as Arun. How many days more would Akhil take to complete the work?
Options- A. 24.5 days
- B. 26.6 days
- C. 25 days
- D. 20 days Discuss
- 3. P and Q can complete a job in 24 days working together. P alone can complete it in 32 days. Both of them worked together for 8 days and then P left. The number of days Q will take to complete the remaining work is ?
Options- A. 56 days
- B. 54 days
- C. 60 days
- D. 64 days Discuss
- 4. If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days what is time taken by 15 men and 20 boys?
Options- A. 4 days
- B. 6 days
- C. 7 days
- D. 5 days Discuss
- 5. P alone can do a piece of work in 24 days. The time taken by P to complete one-third of work is equal to time taken by Q to complete half of the work. How many days are required to complete by P and Q working together ?
Options- A. 9 3/5 days
- B. 7 days
- C. 6 3/7 days
- D. 8 days Discuss
- 6. 4 men and 6 women can complete a work in 8 days, while 3 men and 7 women can complete it in 10 days. In how many days will 10 women complete it ?
Options- A. 40 days
- B. 36 days
- C. 32 days
- D. 34 days Discuss
- 7. 12 men complete a work in 9 days. After they have worked for 6 days, 4 more men join them. How many days will they take to complete the remaining work ?
Options- A. 2 days
- B. 2.5 days
- C. 2.25 days
- D. 3 days Discuss
- 8. M can complete a piece of work in 10 days. N is 33.33% less efficient than M. calculate the number of days required to both to complete the work?
Options- A. 6 days
- B. 8 days
- C. 11 days
- D. 13 days Discuss
- 9. Four pipes P,Q, R and S can fill a cistern in 20,25, 40 and 50 hours respectively.The first pipe P was opened at 6:00 am, Q at 8:00 am, R at 9:00 am and S at 10:00 am. when will the Cistern be full?
Options- A. 4:18 pm
- B. 3:09 pm
- C. 12:15 pm
- D. 11:09 am Discuss
- 10. P is 30% more efficient than Q. How much time will they, working together, take to complete a job which P alone could have done in 23 days?
Options- A. 16 days
- B. 13 days
- C. 15 days
- D. 12 days Discuss
Time and Work problems
Search Results
Correct Answer: 4 days
Explanation:
Given 10 men take 15 days to complete a work
=> Total mandays = 15 x 10 = 150
Let the work be 150 mandays.
=> Now 37 men can do 150 mandays in 150/37 =~ 4 days
Correct Answer: 26.6 days
Explanation:
Arun has completed rd of the work in 8 days
Then he can complete the total work in
---- 8
1 ---- ?
= 24 days
But given Akhil is only 60% as efficient as Arun
Akhil =
Akhil can complete the total work in 40 days
Now, remaining 2/3rd of work can be completed in
1 ------ 40
------ ?
= 26.66 days.
Correct Answer: 64 days
Explanation:
(P+Q)'s 1 day work = 1/24
P's 1 day work = 1/32
=> Q's 1 day work = 1/24 - 1/32 = 1/96
Work done by (P+Q) in 8 days = 8/24 = 1/3
Remainining work = 1 - 1/3 = 2/3
Time taken by Q to complete the remaining work = 2/3 x 96 = 64 days.
Correct Answer: 4 days
Explanation:
Given that
6 men and 8 boys can do a piece of work in 10 days
26 men and 48 boys can do the same in 2 days
As the work done is equal,
10(6M + 8B) = 2(26M + 48B)
60M + 80B = 52M + 96B
=> M = 2B
=> B = M/2 ??(1)
Now Put (1) in 15M + 20B
=> 15M + 10M = 25M
Now, 6M + 8B in 10 days
=> (6M + 4M) 10 = 100M
Then D(25M) = 100M
=> D = 4 days.
Correct Answer: 9 3/5 days
Explanation:
Let the total work be 'W'
As per the given information,
P can complete the work 'W' in 24 days.
=> one day work of P = W/24
And also given that,
The time taken by P to complete one-third of work is equal to time taken by Q to complete half of the work
=> PW/3 = QW/2
=> P's
1 day = W/24
? = W/3
=> ? = 24W/3W = 8
=> QW/2 = 8 days
=> Q alone can complete the work W in 16 days
=> P + Q can complete the work in
1/24 + 1/16 = 5/48
=> 48/5 days = 9 3/5 days.
Correct Answer: 40 days
Explanation:
Let 1 man's 1 day work = x and 1 woman's 1 day work = y.
Then, 4x + 6y = 1/8 and 3x + 7y = 1/10
Solving these two equations, we get:
x = 11/400 and y = 1/400
10 woman's 1 day work = (1/400 x 10) = 1/40.
Hence, 10 women will complete the work in 40 days.
Correct Answer: 2.25 days
Explanation:
1 man's 1 day work = 1/108
12 men's 6 day's work = 1/9 x 6 = 2/3
Remaining work = 1 - 2/3 = 1/3
16 men's 1 day work = 1/108 x 16 = 4/27
4/27 work is done by them in 1 day.
1/3 work is done by them in 27/4 x 1/3 = 9/4 days.
Correct Answer: 6 days
Explanation:
M = 10 days
The ratio of efficiency of M & N are 3 : 2
Hence, the time rquired for N alone = 15 days
=> Required time taken t=by both to complete the work = M x N / M + N
= 10 x 15/ 10 + 15
= 150/25
= 6 days.
Correct Answer: 3:09 pm
Explanation:
Efficiency of P= 100/20= 5% per hour
Efficiency of Q= 100/25= 4% per hour
Efficiency of R= 100/40= 2.5% per hour
Efficiency of S=100/50= 2% per hour
Cistern filled till 10 am by P, Q and R
Thus, at 10 am pipe P,Q and R filled 30.5% of the cistern.
Rest of cistern to be filled = 100 - 30.5 = 69.5%
Now, the time taken by P,Q,R and S together to fill the remaining capacity of the cistern
= 69.5 / (5+4+2.5+2) = 5 Hours and 9 minutes(approx).
Therefore, total time =4 hrs + 5hrs 9 mins = 9 hrs and 9 mins
It means cistern will be filled up at 3:09 pm
Correct Answer: 13 days
Explanation:
Ratio of times taken by P & Q = 100 : 130 = 10:13
Let Q takes x days to do the work
Then, 10:13 :: 23:x
=> x = 23x13/10
=> x = 299/10
P's 1 day's work = 1/23
Q's 1 day's work = 10/299
(P+Q)'s 1 day's work = (1/23 + 10/299) = 23/299 = 1/13
Hence, P & Q together can complete the work in 13 days.
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