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- Question
If 10 men take 15 days to complete a work. In how many days will 37 men complete the work?
Options- A. 3 days
- B. 4 days
- C. 5 days
- D. 6 days
- Correct Answer
- 4 days
ExplanationGiven 10 men take 15 days to complete a work
=> Total mandays = 15 x 10 = 150
Let the work be 150 mandays.
=> Now 37 men can do 150 mandays in 150/37 =~ 4 days
- 1. After working for 8 days, Arun finds that only 13 rd of the work has been done. He employs Akhil who is 60% as efficient as Arun. How many days more would Akhil take to complete the work?
Options- A. 24.5 days
- B. 26.6 days
- C. 25 days
- D. 20 days Discuss
- 2. P and Q can complete a job in 24 days working together. P alone can complete it in 32 days. Both of them worked together for 8 days and then P left. The number of days Q will take to complete the remaining work is ?
Options- A. 56 days
- B. 54 days
- C. 60 days
- D. 64 days Discuss
- 3. If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days what is time taken by 15 men and 20 boys?
Options- A. 4 days
- B. 6 days
- C. 7 days
- D. 5 days Discuss
- 4. P alone can do a piece of work in 24 days. The time taken by P to complete one-third of work is equal to time taken by Q to complete half of the work. How many days are required to complete by P and Q working together ?
Options- A. 9 3/5 days
- B. 7 days
- C. 6 3/7 days
- D. 8 days Discuss
- 5. Amit can do a piece of work in 45 days, but Bharath can do the same work in 5 days less, than Amit, when working alone. Amit and Bharath both started the work together but Bharath left after some days and Amit finished the remaining work in 56 days with half of his efficiency but he did the work with Bharath with his complete efficiency. For how many days they had worked together?
Options- A. 6
- B. 8
- C. 9
- D. 12 Discuss
- 6. 6 men can complete a piece of work in 12 days. 8 women can complete the same piece of work in 18 days whereas 18 children can complete the piece of work in 10 days. 4 men, 12 women and 20 children work together for 2 days. If only men were to complete the remaining work in 1 day how many men would be required totally?
Options- A. 38
- B. 72
- C. 36
- D. 76 Discuss
- 7. 4 men and 6 women can complete a work in 8 days, while 3 men and 7 women can complete it in 10 days. In how many days will 10 women complete it ?
Options- A. 40 days
- B. 36 days
- C. 32 days
- D. 34 days Discuss
- 8. 12 men complete a work in 9 days. After they have worked for 6 days, 4 more men join them. How many days will they take to complete the remaining work ?
Options- A. 2 days
- B. 2.5 days
- C. 2.25 days
- D. 3 days Discuss
- 9. M can complete a piece of work in 10 days. N is 33.33% less efficient than M. calculate the number of days required to both to complete the work?
Options- A. 6 days
- B. 8 days
- C. 11 days
- D. 13 days Discuss
- 10. Four pipes P,Q, R and S can fill a cistern in 20,25, 40 and 50 hours respectively.The first pipe P was opened at 6:00 am, Q at 8:00 am, R at 9:00 am and S at 10:00 am. when will the Cistern be full?
Options- A. 4:18 pm
- B. 3:09 pm
- C. 12:15 pm
- D. 11:09 am Discuss
Time and Work problems
Search Results
Correct Answer: 26.6 days
Explanation:
Arun has completed rd of the work in 8 days
Then he can complete the total work in
---- 8
1 ---- ?
= 24 days
But given Akhil is only 60% as efficient as Arun
Akhil =
Akhil can complete the total work in 40 days
Now, remaining 2/3rd of work can be completed in
1 ------ 40
------ ?
= 26.66 days.
Correct Answer: 64 days
Explanation:
(P+Q)'s 1 day work = 1/24
P's 1 day work = 1/32
=> Q's 1 day work = 1/24 - 1/32 = 1/96
Work done by (P+Q) in 8 days = 8/24 = 1/3
Remainining work = 1 - 1/3 = 2/3
Time taken by Q to complete the remaining work = 2/3 x 96 = 64 days.
Correct Answer: 4 days
Explanation:
Given that
6 men and 8 boys can do a piece of work in 10 days
26 men and 48 boys can do the same in 2 days
As the work done is equal,
10(6M + 8B) = 2(26M + 48B)
60M + 80B = 52M + 96B
=> M = 2B
=> B = M/2 ??(1)
Now Put (1) in 15M + 20B
=> 15M + 10M = 25M
Now, 6M + 8B in 10 days
=> (6M + 4M) 10 = 100M
Then D(25M) = 100M
=> D = 4 days.
Correct Answer: 9 3/5 days
Explanation:
Let the total work be 'W'
As per the given information,
P can complete the work 'W' in 24 days.
=> one day work of P = W/24
And also given that,
The time taken by P to complete one-third of work is equal to time taken by Q to complete half of the work
=> PW/3 = QW/2
=> P's
1 day = W/24
? = W/3
=> ? = 24W/3W = 8
=> QW/2 = 8 days
=> Q alone can complete the work W in 16 days
=> P + Q can complete the work in
1/24 + 1/16 = 5/48
=> 48/5 days = 9 3/5 days.
Correct Answer: 8
Explanation:
Amit did the work in 56 days =
Therefore, Rest work 17/45 was done by Amit and Bharath = = 8 days
( since Amit and Bharath do the work in one day = )
Correct Answer: 36
Explanation:
Given 4men, 12 women and 20 children work for 2 days.
Workdone for 2 days by 4men, 12 women and 20 children =
Therefore, remaining work = 1 - =
To complete the same work by only men in 1 day,
We know that M1 x D1 = M2 x D2
Here M1 = 6 , D1 = 12 and M2 = M , D2 = 1
12 x 6 = M x 1
=> M = 12 x 6 = 72
=> But the remaining work = 1/2
Men required => 1/2 x 72 = 36
Only men required to Complete the remaining work in 1 day = 36.
Correct Answer: 40 days
Explanation:
Let 1 man's 1 day work = x and 1 woman's 1 day work = y.
Then, 4x + 6y = 1/8 and 3x + 7y = 1/10
Solving these two equations, we get:
x = 11/400 and y = 1/400
10 woman's 1 day work = (1/400 x 10) = 1/40.
Hence, 10 women will complete the work in 40 days.
Correct Answer: 2.25 days
Explanation:
1 man's 1 day work = 1/108
12 men's 6 day's work = 1/9 x 6 = 2/3
Remaining work = 1 - 2/3 = 1/3
16 men's 1 day work = 1/108 x 16 = 4/27
4/27 work is done by them in 1 day.
1/3 work is done by them in 27/4 x 1/3 = 9/4 days.
Correct Answer: 6 days
Explanation:
M = 10 days
The ratio of efficiency of M & N are 3 : 2
Hence, the time rquired for N alone = 15 days
=> Required time taken t=by both to complete the work = M x N / M + N
= 10 x 15/ 10 + 15
= 150/25
= 6 days.
Correct Answer: 3:09 pm
Explanation:
Efficiency of P= 100/20= 5% per hour
Efficiency of Q= 100/25= 4% per hour
Efficiency of R= 100/40= 2.5% per hour
Efficiency of S=100/50= 2% per hour
Cistern filled till 10 am by P, Q and R
Thus, at 10 am pipe P,Q and R filled 30.5% of the cistern.
Rest of cistern to be filled = 100 - 30.5 = 69.5%
Now, the time taken by P,Q,R and S together to fill the remaining capacity of the cistern
= 69.5 / (5+4+2.5+2) = 5 Hours and 9 minutes(approx).
Therefore, total time =4 hrs + 5hrs 9 mins = 9 hrs and 9 mins
It means cistern will be filled up at 3:09 pm
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