Arun has completed rd of the work in 8 days
Then he can complete the total work in
---- 8
1 ---- ?
= 24 days
But given Akhil is only 60% as efficient as Arun
Akhil =
Akhil can complete the total work in 40 days
Now, remaining 2/3rd of work can be completed in
1 ------ 40
------ ?
= 26.66 days.
(P+Q)'s 1 day work = 1/24
P's 1 day work = 1/32
=> Q's 1 day work = 1/24 - 1/32 = 1/96
Work done by (P+Q) in 8 days = 8/24 = 1/3
Remainining work = 1 - 1/3 = 2/3
Time taken by Q to complete the remaining work = 2/3 x 96 = 64 days.
Given that
6 men and 8 boys can do a piece of work in 10 days
26 men and 48 boys can do the same in 2 days
As the work done is equal,
10(6M + 8B) = 2(26M + 48B)
60M + 80B = 52M + 96B
=> M = 2B
=> B = M/2 ??(1)
Now Put (1) in 15M + 20B
=> 15M + 10M = 25M
Now, 6M + 8B in 10 days
=> (6M + 4M) 10 = 100M
Then D(25M) = 100M
=> D = 4 days.
Let the total work be 'W'
As per the given information,
P can complete the work 'W' in 24 days.
=> one day work of P = W/24
And also given that,
The time taken by P to complete one-third of work is equal to time taken by Q to complete half of the work
=> PW/3 = QW/2
=> P's
1 day = W/24
? = W/3
=> ? = 24W/3W = 8
=> QW/2 = 8 days
=> Q alone can complete the work W in 16 days
=> P + Q can complete the work in
1/24 + 1/16 = 5/48
=> 48/5 days = 9 3/5 days.
Amit did the work in 56 days =
Therefore, Rest work 17/45 was done by Amit and Bharath = = 8 days
( since Amit and Bharath do the work in one day = )
Let 'B' alone can do the work in 'x' days
6/30 + 18/x = 1
=> x = 22.5
1/30 + 1/22.5 = 7/90
=> 90/7 = 12 6/7 days
Given 10 men take 15 days to complete a work
=> Total mandays = 15 x 10 = 150
Let the work be 150 mandays.
=> Now 37 men can do 150 mandays in 150/37 =~ 4 days
Given 4men, 12 women and 20 children work for 2 days.
Workdone for 2 days by 4men, 12 women and 20 children =
Therefore, remaining work = 1 - =
To complete the same work by only men in 1 day,
We know that M1 x D1 = M2 x D2
Here M1 = 6 , D1 = 12 and M2 = M , D2 = 1
12 x 6 = M x 1
=> M = 12 x 6 = 72
=> But the remaining work = 1/2
Men required => 1/2 x 72 = 36
Only men required to Complete the remaining work in 1 day = 36.
Let 1 man's 1 day work = x and 1 woman's 1 day work = y.
Then, 4x + 6y = 1/8 and 3x + 7y = 1/10
Solving these two equations, we get:
x = 11/400 and y = 1/400
10 woman's 1 day work = (1/400 x 10) = 1/40.
Hence, 10 women will complete the work in 40 days.
1 man's 1 day work = 1/108
12 men's 6 day's work = 1/9 x 6 = 2/3
Remaining work = 1 - 2/3 = 1/3
16 men's 1 day work = 1/108 x 16 = 4/27
4/27 work is done by them in 1 day.
1/3 work is done by them in 27/4 x 1/3 = 9/4 days.
M = 10 days
The ratio of efficiency of M & N are 3 : 2
Hence, the time rquired for N alone = 15 days
=> Required time taken t=by both to complete the work = M x N / M + N
= 10 x 15/ 10 + 15
= 150/25
= 6 days.
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