Let the total work be 'W'
As per the given information,
P can complete the work 'W' in 24 days.
=> one day work of P = W/24
And also given that,
The time taken by P to complete one-third of work is equal to time taken by Q to complete half of the work
=> PW/3 = QW/2
=> P's
1 day = W/24
? = W/3
=> ? = 24W/3W = 8
=> QW/2 = 8 days
=> Q alone can complete the work W in 16 days
=> P + Q can complete the work in
1/24 + 1/16 = 5/48
=> 48/5 days = 9 3/5 days.
47/10000 = .0047
.02 =(2/100) x 100% =2%
Let N / 11 = 233
Then, N = 233 x 11 = 2563
? Missing digit is 5.
121012 = 12 x 10084 + 4
? remainder = 4
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
Subtract 20, 25, 30, 35, 40, 45 from successive numbers. So 0 is wrong.
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