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- Question
10 men and 15 women together can complete a work in 6 days. It takes 100 days for one man alone to complete the same work. How many days will be required for one woman alone to complete the same work?
Options- A. 215 days
- B. 225 days
- C. 235 days
- D. 240 days
- Correct Answer
- 225 days
ExplanationGiven that
(10M + 15W) x 6 days = 1M x 100 days
=> 60M + 90W = 100M
=> 40M = 90W
=> 4M = 9W.
From the given data,
1M can do the work in 100 days
=> 4M can do the same work in 100/4= 25 days.
=> 9W can do the same work in 25 days.
=> 1W can do the same work in 25 x 9 = 225 days.
Hence, 1 woman can do the same work in 225 days.
- 1. If 2 men and 3 women can do a piece of work in 8 days and 3 men and 2 women in 7 days. In how many days can the work be done by 5 men and 4 women working together?
Options- A. 3 days
- B. 6 days
- C. 4 days
- D. 2 days Discuss
- 2. A and B together can do a piece of work in 40 days. A having worked for 20 days, B finishes the remaining work alone in 60 days. In How many days shall B finish the whole work alone?
Options- A. 60
- B. 70
- C. 80
- D. 90 Discuss
- 3. 4 men can repair a road in 7 hours. How many men are required to repair the road in 2 hours ?
Options- A. 17 men
- B. 14 men
- C. 13 men
- D. 16 men Discuss
- 4. When A, B and C are deployed for a task , A and B together do 70% of the work and B and C together do 50% of the work. who is most efficient?
Options- A. A
- B. B
- C. C
- D. can't be determined Discuss
- 5. 16 women can do a piece of work in 10 days while 15 men can do the same work in 12 days. All men and all women work alternately starting with all men, then find the time taken by them to complete the whole work?
Options- A. 10 5/2 days
- B. 11 days
- C. 11 2/5 days
- D. 12 1/2 days Discuss
- 6. A can finish a work in 18 days and B can do the same work in half the time taken by A. then, working together, what part of the same work they can finish in a day ?
Options- A. Total work
- B. One-fourth work
- C. Half work
- D. Two-third work Discuss
- 7. A can do a piece of work in 30 days. He works at it for 6 days and then B finishes it in 18 days. In what time can A and B together it ?
Options- A. 14 1/2 days
- B. 11 days
- C. 13 1/4 days
- D. 12 6/7 days Discuss
- 8. Amit can do a piece of work in 45 days, but Bharath can do the same work in 5 days less, than Amit, when working alone. Amit and Bharath both started the work together but Bharath left after some days and Amit finished the remaining work in 56 days with half of his efficiency but he did the work with Bharath with his complete efficiency. For how many days they had worked together?
Options- A. 6
- B. 8
- C. 9
- D. 12 Discuss
- 9. P alone can do a piece of work in 24 days. The time taken by P to complete one-third of work is equal to time taken by Q to complete half of the work. How many days are required to complete by P and Q working together ?
Options- A. 9 3/5 days
- B. 7 days
- C. 6 3/7 days
- D. 8 days Discuss
- 10. If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days what is time taken by 15 men and 20 boys?
Options- A. 4 days
- B. 6 days
- C. 7 days
- D. 5 days Discuss
Time and Work problems
Search Results
Correct Answer: 4 days
Explanation:
From the given data,
=> (2 M + 3W) 8 = (3M + 2W)7
=> 16M + 24W = 21M + 14 W
=> 10W = 5M
=> 2W = M
=> 14W × ? = 7W × 8
? = 4 days
Correct Answer: 80
Explanation:
Let A's 1 day's work=x and B's 1 day's work=y
Then x+y = 1/40 and 20x+60y=1
Solving these two equations , we get : x= 1/80 and y= 1/80
Therefore B's 1 day work = 1/80
Hence,B alone shall finish the whole work in 80 days
Correct Answer: 14 men
Explanation:
M x T / W = Constant
where, M= Men (no. of men)
T= Time taken
W= Work load
So, here we apply
M1 x T1/ W1 = M2 x T2 / W2
Given that, M1 = 4 men, T1 = 7 hours ; T2 = 2 hours, we have to find M2 =?
Note that here, W1 = W2 = 1 road, ie. equal work load.
Clearly, substituting in the above equation we get, M2 = 14 men.
Correct Answer: A
Explanation:
A + B= 70%
B + C =50%
=> B= 20% A= 50% and C=30%
Hence A is most efficient
Correct Answer: 10 5/2 days
Explanation:
Let efficiency of every man and every woman be 'm' unit/day and 'w' unit/day respectively
15×12×m = 10×16×w
? m/w = 8/9
Total work = 15 × 12 × 9 = 1620 units
In 2 days, total work done = 15 x 9 + 16 x 8 = 263 units
So, in 10 days work done will be = 263 × 5 = 1315 units
Remaining work will be done in = (1620-1315)/(15×8) = 5/2 days
Total days = 10 5/2 days.
Correct Answer: Half work
Explanation:
A can do the work = 18 days
B can do the work = 18/2 = 9 days
(A + B)'s 1 day work = 1/18 + 1/9 = 1/6
=> In 3 days = 3x1/6 = 1/2 work is completed.
Correct Answer: 12 6/7 days
Explanation:
Let 'B' alone can do the work in 'x' days
6/30 + 18/x = 1
=> x = 22.5
1/30 + 1/22.5 = 7/90
=> 90/7 = 12 6/7 days
Correct Answer: 8
Explanation:
Amit did the work in 56 days =
Therefore, Rest work 17/45 was done by Amit and Bharath = = 8 days
( since Amit and Bharath do the work in one day = )
Correct Answer: 9 3/5 days
Explanation:
Let the total work be 'W'
As per the given information,
P can complete the work 'W' in 24 days.
=> one day work of P = W/24
And also given that,
The time taken by P to complete one-third of work is equal to time taken by Q to complete half of the work
=> PW/3 = QW/2
=> P's
1 day = W/24
? = W/3
=> ? = 24W/3W = 8
=> QW/2 = 8 days
=> Q alone can complete the work W in 16 days
=> P + Q can complete the work in
1/24 + 1/16 = 5/48
=> 48/5 days = 9 3/5 days.
Correct Answer: 4 days
Explanation:
Given that
6 men and 8 boys can do a piece of work in 10 days
26 men and 48 boys can do the same in 2 days
As the work done is equal,
10(6M + 8B) = 2(26M + 48B)
60M + 80B = 52M + 96B
=> M = 2B
=> B = M/2 ??(1)
Now Put (1) in 15M + 20B
=> 15M + 10M = 25M
Now, 6M + 8B in 10 days
=> (6M + 4M) 10 = 100M
Then D(25M) = 100M
=> D = 4 days.
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