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- Question
A missile travels at 1422 km/h. How many metres does it travel in one second?
Options- A. 395 metres
- B. 400 metres
- C. 364 metres
- D. 319 metres
- Correct Answer
- 395 metres
- 1.
If x = 2 + ?3, y = 2 - ?3, then the value of x 2 + y 2 is x3 + y3
Options- A. 7 38
- B. 7 40
- C. 7 19
- D. 7 26 Discuss
- 2. Which of the following pairs of sets are comparable?
Options- A. A = {1, 3, 5}, and B = {3, 2, 5, 6}
- B. A = {x: x ? N and x ? 10} and B = {1, 2, 3,?, 10, 11}
- C. A = {1, 2, 3, {4, 5}}, and B = {1, 2, 3, 4, 5}.
- D. None of these Discuss
- 3. In an examination, 30% of the total students failed in Hindi, 45% failed in English and 20% failed in both the subjects. Find the percentage of those who passed in both the subjects.
Options- A. 35.7%
- B. 35%
- C. 40%
- D. 45% Discuss
- 4. There are 80 families in a small extension area. 20 per cent of these families own a car each. 50 per cent of the remaining families own a motor cycle each. How many families in that extension do not own any vehicle?
Options- A. 30
- B. 32
- C. 23
- D. 36 Discuss
- 5. 10 yr before, the ratio of ages of A and B was 13 : 17. After 17 yr from now, the ratio of their ages will be 10 : 11. The present age of B is
Options- A. 23 yr
- B. 40 yr
- C. 27 yr
- D. 44 yr Discuss
- 6. Which of the following sets is infinite?
Options- A. {x: x is a prime number, x is even}
- B. Set of all river in India
- C. Set of all concentric circles
- D. None of above Discuss
- 7. Mangulal a shopkeeper, marks the prices of his goods at 20% higher than the original price. After that he allows a discount of 5%. What profit or loss did he get?
Options- A. 14% (profit)
- B. 14% (loss)
- C. 16% (loss)
- D. 16% (profit) Discuss
- 8. In a class, 50 students play cricket, 20 students play football and 10 play both cricket and football. How many play at least one of these two games?
Options- A. 60
- B. 45
- C. 55
- D. 65 Discuss
- 9. Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If mixture is worth Rs. 153 per kg, the price of the third variety per kg will be:
Options- A. 180
- B. 175.50
- C. 170
- D. 169.50 Discuss
- 10. If A and B are two sets such that A has 40 elements, A ? B has 60 elements and A ? B has 10 elements, how many elements does B have?
Options- A. 40
- B. 30
- C. 45
- D. 50 Discuss
More questions
Correct Answer: 7 26
Explanation:
Correct Answer: A = {x: x ? N and x ? 10} and B = {1, 2, 3,?, 10, 11}
Explanation:
(a) 1? A but 1? B and 6 ? B but 6 ? A.
? A and B are not comparable.
(b) A = {x: x ? N and x ? 10} = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} B = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11}
Clearly, A ? B ? A and B are comparable.
(c) {4, 5} ? A but {4, 5} ? B and 4 ? B but 4 ? A.
? A and B are not comparable.
Correct Answer: 45%
Explanation:
Let the number of students be 100. Number of students who failed in Hindi is 30%.
n(H) = 30
Number of students who failed in English is 45%.
? n(E) = 45
Number of students who failed in both the subjects is 20%. n(H ? E) = 20
Applying the rule,
n(H ? E) = n(H) + n(E) - n(H ? E)
= 30 + 45 - 20 = 55
Percentage of students who failed in Hindi or English or both the subjects = 55%
Number of students who passed in both the subjects = 100 - 55 = 45%
Correct Answer: 32
Explanation:
Given in the question,
20% of 80 = 20 * 80 / 100 = 16
Remaining 50%
= (80 ? 16) × 50 / 100 = 32
No. of families not owning any vehicle
= 80 ? (32 + 16) = 80 ? 48 = 32
Correct Answer: 27 yr
Explanation:
Let the ages of A and B 10 yr before were 13k yr and 17k yr, respectively.
Then, present age of A = 13k + 10
and present age of B = 17k + 10
According to the question,
? (13k + 10 + 17) / (17k + 10 + 17) = 10/11
? (13k + 27) / (17k + 27) = 10/11
? 143k + 297 = 170k + 270
? 27k = 27
? k = 1
Hence, present age of B = 17 x 1 + 10 = 27 yr
Correct Answer: Set of all concentric circles
Explanation:
NA
Correct Answer: 14% (profit)
Explanation:
Given that, a = 20% and b = 5%
According to the formula
Required percentage = [20 - 5 - {20 x (5/100)}% = 14%
Correct Answer: 60
Explanation:
Given: n(C) = 50, n(F) = 20, n(C ? F) = 10.
Number of students playing at least one of these two games = n (C ? F) = n (C) + n (F) ? n (C ? F)
= 50 + 20 ? 10 = 60.
Correct Answer: 175.50
Explanation:
Here first two varieties of tea are mixed in equal ratio.
So their average price = (126 + 135) /2 = Rs. 130.50
Let price of the third variety per kg be Rs. A; then now mixture is formed by two varieties one at Rs. 130.50 per kg and other at Rs. A per kg in the same ratio 2 : 2 i.e, 1 : 1
By the rule of alligation,
(A - 153) / (22.50) = 1
? A ? 153 = 22.50
? A = Rs. 175.50
Correct Answer: 30
Explanation:
Given in the question ,
n(A) = 40, n(A ? B) = 60 and n(A ? B) = 10.
As we know the formula,
n(A ? B) = n(A) + n(B) ? n(A ? B)
Putting these values in the formula, we get
60 = 40 + n(B) ? 10
? n(B) = 30.
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