Discussion
Home ‣ Aptitude ‣ Time and Distance Comments
- Question
An inspector is 228 meter behind the thief. The inspectorruns 42 meters and the thief runs 30 meters in a minute. Inwhat time will the inspector catch the thief?
Options- A. 19 minutes
- B. 20 minutes
- C. 18 minutes
- D. 21 minutes
- Correct Answer
- 19 minutes
ExplanationInspector s 228 meter behind the thief and now aftersome x distance he will catch the thief. So
x/30 = 228+x/42 => x = 570 m
(228 + 570) / 42 = 19 min - 1. Running 3/4th of his usual rate, a man is 15min late. Find his usual time in hours ?
Options- A. 2/3 hrs
- B. 3/4 hrs
- C. 1/3 hrs
- D. 1/4 hrs Discuss
- 2. A Bus is running at 9/10 of its own speed reached a place in 22 hours. How much time could be saved if the bus would run at its own speed ?
Options- A. 1.5 hrs
- B. 1.7 hrs
- C. 2.2 hrs
- D. 3.5 hrs Discuss
- 3. A Bus travels first half distance between two places with a speed of 40 kmph and the rest half distance with a speed of 60 kmph. The average speed of the Bus is ?
Options- A. 48 kmph
- B. 50 kmph
- C. 46 kmph
- D. 42 kmph Discuss
- 4. Two stations A and B are 200 km apart on a straight track. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?
Options- A. 12 a.m.
- B. 1 p.m.
- C. 11 a.m.
- D. 12 p.m. Discuss
- 5. B starts 4.5 minutes after A from the same point, for a place at a distance of 3.5 miles from the starting point. A on reaching the destination turns back and walk a mile where he meets B. If A's speed is a mile in 6 minutes then B's speed is a mile in ____ minutes?
Options- A. 8
- B. 10
- C. 12
- D. 9 Discuss
- 6. An object travels 23 m in 3 s and then another 15 m in 2 s. What is the average speed of the object?
Options- A. 7.6 m/s
- B. 8.0 m/s
- C. 7.6 m
- D. 8.0 s Discuss
- 7. Vishnu travelled equal distances at speeds of 10 kmph, 30 kmph and 8 kmph and took a total of 15.5 min to complete. Find the total distance he travelled, in km.
Options- A. 1
- B. 3
- C. 4
- D. 2 Discuss
- 8. Two buses travel to a place at 45 km/hr and 60 km/hr respectively. If the second bus takes 51?2 hours less than the first for the journey, the length of the journey is:
Options- A. 900 km
- B. 940 km
- C. 990 km
- D. 1300 km Discuss
- 9. A car runs at the speed of 50 kms per hour when not serviced and runs at 60 km./hr. when serviced. After servicing the car covers a certain distance in 6 hours. How much time will the car take to cover the same distance when not serviced?
Options- A. 8.2 hrs
- B. 6.5 hrs
- C. 8 hrs
- D. 7.2 hrs Discuss
- 10. A boy starts from his house and walks at a speed of 5 km/hr and reaches his school 3 minutes late. Next day he starts at the same time and increases hisspeed by 4 km/hr and reaches 3 minutes early. What is the distance (in km) between the school and his house?
Options- A. 1
- B. 1.25
- C. 1.125
- D. 1.5 Discuss
Time and Distance problems
Search Results
Correct Answer: 3/4 hrs
Explanation:
Walking at 3/4th of usual rate implies that time taken would be 4/3th of the usual time. In other words, the time taken is 1/3rd more than his usual time
so 1/3rd of the usual time = 15min
or usual time = 3 x 15 = 45min = 45/60 hrs = 3/4 hrs.
Correct Answer: 2.2 hrs
Explanation:
Let the original Speed be "s" kmph
And the usual time be "t" hrs
Given that if the bus is running at 9s/10 kmph the time is 22 hrs
=> [9s/10] x 22 = t x s
=> 99/5 = t
=> t = 19.8 hrs
Hence, if bus runs at its own speed, the time saved = 22 - 19.8 = 2.2 hrs.
Correct Answer: 48 kmph
Explanation:
we know that speed = distance traveled/time taken
let the total distance traveled by the car is 2x km.
then time taken by it to cover first half is x/60 hour.
and for second half is x/40 hour.
Then average speed= total distance travelled / total time taken.
i.e.
=>
= 48 kmph.
Correct Answer: 12 p.m.
Explanation:
Assume both trains meet after 'p' hours after 7 a.m.
Distance covered by train starting from A in 'p' hours = 20p km
Distance covered by train starting from B in (p-1) hours = 25(p-1)
Total distance = 200
=> 20x + 25(x-1) = 200
=> 45x = 225
=> p= 5
Means, they meet after 5 hours after 7 am, ie, they meet at 12 p.m.
Correct Answer: 9
Correct Answer: 7.6 m/s
Correct Answer: 3
Correct Answer: 990 km
Correct Answer: 7.2 hrs
Explanation:
After servicing, the distance covered by car in 6 hours = 60 * 6 = 360 km Without servicing, speed of car = 50 kmph => Required time = Distance/speed = 360/50 = 7.2 hrs.
Correct Answer: 1.125
Comments
There are no comments.More in Aptitude:
Programming
Copyright ©CuriousTab. All rights reserved.