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- Question
Two persons start running simultaneously around a circular track of length 600 m from the same point at speeds of 25 kmph and 35 kmph. When will they meet for the first time any where on the track ?
Options- A. 54 sec
- B. 36 sec
- C. 72 sec
- D. 11 sec
- Correct Answer
- 36 sec
ExplanationTime taken to meet the first time = length of track/relative speed
Given the length of the track is 600 m
The relative speed = 25 + 35 = 60 kmph = 60 x 5/18 m
Therefore Time = = 600/60 x (18/5) = 36 sec.
- 1. Two motor bikes cover the same distance at the speed of 60 and 64 kmps respectively. Find the distance traveled by them if the slower bike takes 1 hour more than the faster bike ?
Options- A. 1102 km
- B. 1060 km
- C. 960 km
- D. 1250 km Discuss
- 2. A man walks at a speed of 2 km/hr and runs at a speed of 6 km/hr. How much time will the man require to cover a distance of 20 1/2 km, if he completes half of the distance, i.e., (10 1/4) km on foot and the other half by running ?
Options- A. 12.4 hrs
- B. 11.9 hrs
- C. 10.7 hrs
- D. 9.9 hrs Discuss
- 3. Ramu rides his bike at an average speed of 45 km/hr and reaches his desitination in four hours. Somu covers the same distance in six hours. If Ramu covered his journey at an average speed which was 9 km/hr less and Somu covered his journey at an average speed which was 10 km/hr more, then the difference in their times taken to reach the destination would be (in minutes).
Options- A. 18 min
- B. 30 min
- C. 27 min
- D. 32 min Discuss
- 4. Two men A and B start from place X walking at 4 ½ kmph and 5 ¾ kmph respectively. How many km apart they are at the end of 3 ½ hours if they are walking in the same direction ?
Options- A. 2 9/7 km
- B. 3 7/5 km
- C. 1 3/4 km
- D. 4 3/8 km Discuss
- 5. In a race of 200 m, A can beat B by 31 m and C by 18 m. In a race of 350 m, C will beat B by ?
Options- A. 25 m
- B. 21 m
- C. 22 m
- D. 19 m Discuss
- 6. Radha and Hema are neighbours and study in the same school. Both of them use bicycles to go to the school. Radha?s speed is 8 km/hr whereas Hema?s speed is 10 km/hr. Hema takes 9 minutes less than Radha to reach the school. How far is the school from the locality of Radha and Hema?
Options- A. 5 km
- B. 5.5 km
- C. 6 km
- D. 6.5 km Discuss
- 7. Tilak rides on a cycle to a place at speed of 22 kmph and comes back at a speed of 20 kmph. If the time taken by him in the second case is 36 min. more than that of the first case, what is the total distance travelled by him (in km)?
Options- A. 132 km
- B. 264 km
- C. 134 km
- D. 236 km Discuss
- 8. In a race of 800m Kaushik gives Piyush a start of 200m and then loses the race by 20 seconds. What is the speed of Piyush and Kaushik respectively ? If the ratio of respective speeds be 3:2.
Options- A. 15 m/s
- B. 20 m/s
- C. 25 m/s
- D. 30 m/s Discuss
- 9. Two trains starting at the same time from two stations 200 km apart and going in opposite directions cross each other at a distance of 110 km from one of the stations. What is the ratio of their speeds?
Options- A. 9 : 20
- B. 11 : 9
- C. 11 : 20
- D. None of these Discuss
- 10. If a student walks at the rate of 4 mts/min from his home, he is 4 minutes late for school, if he walks at the rate of 6 mts/min he reaches half an hour earlier. How far is his school from his home ?
Options- A. 100 mts
- B. 96 mts
- C. 98 mts
- D. 120 mts Discuss
Time and Distance problems
Search Results
Correct Answer: 960 km
Explanation:
60(x + 1) = 64x
X = 15
60 x 16 = 960 km
Correct Answer: 11.9 hrs
Explanation:
We know that
Time = Distance/speed
Required time = (10 1/4)/2 + (10 1/4)/6
= 41/8 + 41/6
= 287/24 = 11.9 hours.
Correct Answer: 30 min
Explanation:
Distance travelled by Ramu = 45 x 4 = 180 km
Somu travelled the same distance in 6 hours.
His speed = 180/6 = 30 km/hr
Hence in the conditional case, Ramu's speed = 45 - 9 = 36 km/hr and Somu's speed = 30 + 10 = 40km/hr.
Therefore travel time of Ramu and Somu would be 5 hours and 4.5 hours respectively.
Hence difference in the time taken = 0.5 hours = 30 minutes.
Correct Answer: 4 3/8 km
Explanation:
Relative Speed = 5 ¾ - 4 ½ = 1 ¼
Time = 3 ½ h.
Distance = 5/4 x 7/2 = 35/8 = 4 3/8 km.
Correct Answer: 25 m
Explanation:
A:B = 200 : 169
A:C = 200 : 182
=> 182:169
When C covers 182 m , B Covers 169 m
When C covers 350 m , B Covers
=> 325 m
So C beats B by (350 - 325) = 25 m.
Correct Answer: 6 km
Explanation:
Correct Answer: 264 km
Explanation:
Let the distance travelled by Tilak in first case or second case = d kms
Now, from the given data,
d/20 = d/22 + 36 min
=> d/20 = d/22 + 3/5 hrs
=> d = 132 km.
Hence, the total distance travelled by him = d + d = 132 + 132 = 264 kms.
Correct Answer: 20 m/s
Explanation:
Let the speed of Kaushik be Sk and speed of Piyush be Sp Let the time taken by Piyush be t second then, SkSp = 800t+20600t = 23 Since given ratio t = 20 s Speed of Piyush = Sp = 600/20 = 30 m/s Speed of Kaushik = 800/40 = 20 m/s
Correct Answer: 11 : 9
Explanation:
In the same time, they cover 110 km and 90 km respectively.
Therefore, Ratio of their speeds = 110 : 90 = 11 : 9
Correct Answer: 98 mts
Explanation:
Let the distance between home and school is 'x'.
Let actual time to reach be 't'.
Thus, x/4 = t + 4 ---- (1)
and x/6 = t - 30 -----(2)
Solving equation (1) and (2)
=> x = 98 mts.
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