Relative Speed = 5 ¾ - 4 ½ = 1 ¼
Time = 3 ½ h.
Distance = 5/4 x 7/2 = 35/8 = 4 3/8 km.
A:B = 200 : 169
A:C = 200 : 182
=> 182:169
When C covers 182 m , B Covers 169 m
When C covers 350 m , B Covers
=> 325 m
So C beats B by (350 - 325) = 25 m.
Let the distance between A and B = D
Given the speed of maruthi = 60 kmph
Maruthi reaches from A to B in 6 hrs 20 min = 6 + 20/60 = 6 1/3 hrs
Now, the distance between A & B = D = speed x time = 60 x 19/3 = 380 kms
As the distance is same for toyato also,
given time for toyato = 4 hrs 45 min = 4 + 45/60 = 4 3/4 = 19/4 hrs
speed of toyato = distance/time = 380/19/4 = 380 x 4/19 = 80 kmph.
|-----------20--------------------|
50 40
Difference = 20kms
Relative Speed = 50 ? 40 = 10 kmph
Time = 20/10 = 2 hours.
Let the speed of goods truck be 'p' kmph
Distance covered by goods truck in 10hrs (4+6) = Distance covered by other truck in 4 hrs.
10p = 4 x 90
p = 36kmph.
Therefore, the speed of the goods truck is p = 36 kmph.
The first train covers 180 kms in 5 hrs
=> Speed = 180/5 = 36 kmph
Now the second train covers the same distance in 1 hour less than the first train => 4 hrs
=> Speed of the second train = 180/4 = 45 kmph
Now, required difference in distance in 1 hour = 45 - 36 = 9 kms.
Distance travelled by Ramu = 45 x 4 = 180 km
Somu travelled the same distance in 6 hours.
His speed = 180/6 = 30 km/hr
Hence in the conditional case, Ramu's speed = 45 - 9 = 36 km/hr and Somu's speed = 30 + 10 = 40km/hr.
Therefore travel time of Ramu and Somu would be 5 hours and 4.5 hours respectively.
Hence difference in the time taken = 0.5 hours = 30 minutes.
We know that
Time = Distance/speed
Required time = (10 1/4)/2 + (10 1/4)/6
= 41/8 + 41/6
= 287/24 = 11.9 hours.
60(x + 1) = 64x
X = 15
60 x 16 = 960 km
Time taken to meet the first time = length of track/relative speed
Given the length of the track is 600 m
The relative speed = 25 + 35 = 60 kmph = 60 x 5/18 m
Therefore Time = = 600/60 x (18/5) = 36 sec.
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