The first train covers 180 kms in 5 hrs
=> Speed = 180/5 = 36 kmph
Now the second train covers the same distance in 1 hour less than the first train => 4 hrs
=> Speed of the second train = 180/4 = 45 kmph
Now, required difference in distance in 1 hour = 45 - 36 = 9 kms.
Total running distance in four weeks = (24 x 240) + (4 x 400)
= 5760 + 1600
= 7360 meters
= 7360/1000
=> 7.36 kms
Let the speed of the train be 'S' kmph
From the given data,
Distance = Length of train = D = 200 mts = 200 x 18/5 kms
Time = 10 sec
given speed of the motorcycler = 12 kmph
Relative speed as they are moving in the same direction = (S - 12) kmph
Hence, the speed of the train = S = 60 kmph
Now,
Let the speed of the jeep be 'x' kmph
Therefore, the speed of the jeep = x = 24 kmph.
Given Karthik can cover the distance of 200 kms resting 2 hrs per day in 22 days.
Let the initial speed be '1'
Hence, Time = 22(24hrs - 2)
Noe new speed = 2/3
Let the number of days he take be 'D'
Therefore,
D = 11 x 3 x 5/4 = 41.25 days. = 41 1/4 days.
Let P's speed = x km/hr. Then, Q's speed = (7 - x) km/ hr.
So, 24/x + 24/(7 - x) = 14
- 98x + 168 = 0
(x - 3)(x - 4) = 0 => x = 3 or 4.
Since, P is faster than Q,
so P's speed = 4 km/hr and Q's speed = 3 km/hr.
Using pythagarous theorem,
distance travelled by first train = 36x5/18x30 = 300m
distance travelled by second train = 48x5/18x30 = 400m
so distance between them =?( 90000 + 160000) = ?250000 = 500mts.
Let the speed of goods truck be 'p' kmph
Distance covered by goods truck in 10hrs (4+6) = Distance covered by other truck in 4 hrs.
10p = 4 x 90
p = 36kmph.
Therefore, the speed of the goods truck is p = 36 kmph.
|-----------20--------------------|
50 40
Difference = 20kms
Relative Speed = 50 ? 40 = 10 kmph
Time = 20/10 = 2 hours.
Let the distance between A and B = D
Given the speed of maruthi = 60 kmph
Maruthi reaches from A to B in 6 hrs 20 min = 6 + 20/60 = 6 1/3 hrs
Now, the distance between A & B = D = speed x time = 60 x 19/3 = 380 kms
As the distance is same for toyato also,
given time for toyato = 4 hrs 45 min = 4 + 45/60 = 4 3/4 = 19/4 hrs
speed of toyato = distance/time = 380/19/4 = 380 x 4/19 = 80 kmph.
A:B = 200 : 169
A:C = 200 : 182
=> 182:169
When C covers 182 m , B Covers 169 m
When C covers 350 m , B Covers
=> 325 m
So C beats B by (350 - 325) = 25 m.
Relative Speed = 5 ¾ - 4 ½ = 1 ¼
Time = 3 ½ h.
Distance = 5/4 x 7/2 = 35/8 = 4 3/8 km.
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