Using pythagarous theorem,
distance travelled by first train = 36x5/18x30 = 300m
distance travelled by second train = 48x5/18x30 = 400m
so distance between them =?( 90000 + 160000) = ?250000 = 500mts.
Given that,
1st train speed = 62 km/hr
2nd train speed = 44 km/hr
Hence the relative speed of two trains is : 62-44 = 18 km/hr = m/s = 5 m/s.
There fore, the first train crosses the second train i.e (85+75)mts of distance with a speed of 5m/s in,
time = = 32 sec.
Speed of lorry = = 30 kmph
Speed of van = = 75 kmph
Speed of bike = = 45 kmph
Therefore, now required average speed of bike and van = = 60 kmph.
Given speed of the bike after servicing = 55 kmph
Time taken for travelling some distance at 55 kmph = 5 hrs
Then,
Distance = Speed x Time = 55 x 5 = 275 kms.
Now,
Speed of the bike before servicing = 35 kmph
Distance = 275 kms
Now, Time = Distance/Speed = 275/35 = 7.85 hrs =~ 8 hrs.
Man walked 6 km at 1.5 kmph, again he walked 8 km at speed of 2 kmph and 40 km at a speed of 8kmph
time taken indivisually:
=> 6/1.5 = 4 m
=> 8/2 = 4 m
=> 40/8 = 5 m
Average speed of man= total distance/ total time
=> 54/13 =
kmph
To find the minimum distance, we have to get the LCM of 75, 80, 85
Now, LCM of 75, 80, 85 = 5 x 15 x 16 x 17 = 20400
Hence, the minimum distance each should walk so that thay can cover the distance in complete steps = 20400 cms = 20400/100 = 204 mts.
Let P's speed = x km/hr. Then, Q's speed = (7 - x) km/ hr.
So, 24/x + 24/(7 - x) = 14
- 98x + 168 = 0
(x - 3)(x - 4) = 0 => x = 3 or 4.
Since, P is faster than Q,
so P's speed = 4 km/hr and Q's speed = 3 km/hr.
Given Karthik can cover the distance of 200 kms resting 2 hrs per day in 22 days.
Let the initial speed be '1'
Hence, Time = 22(24hrs - 2)
Noe new speed = 2/3
Let the number of days he take be 'D'
Therefore,
D = 11 x 3 x 5/4 = 41.25 days. = 41 1/4 days.
Let the speed of the train be 'S' kmph
From the given data,
Distance = Length of train = D = 200 mts = 200 x 18/5 kms
Time = 10 sec
given speed of the motorcycler = 12 kmph
Relative speed as they are moving in the same direction = (S - 12) kmph
Hence, the speed of the train = S = 60 kmph
Now,
Let the speed of the jeep be 'x' kmph
Therefore, the speed of the jeep = x = 24 kmph.
Total running distance in four weeks = (24 x 240) + (4 x 400)
= 5760 + 1600
= 7360 meters
= 7360/1000
=> 7.36 kms
The first train covers 180 kms in 5 hrs
=> Speed = 180/5 = 36 kmph
Now the second train covers the same distance in 1 hour less than the first train => 4 hrs
=> Speed of the second train = 180/4 = 45 kmph
Now, required difference in distance in 1 hour = 45 - 36 = 9 kms.
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