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- Question
A man whose speed is 4.5 kmph in still water rows to a certain upstream point and back to the starting point in a river which flows at 1.5 kmph, find his average speed for the total journey ?
Options- A. 5 kmph
- B. 7 kmph
- C. 3 kmph
- D. 4 kmph
- Correct Answer
- 4 kmph
ExplanationSpeed of Man = 4.5 kmph
Speed of stream = 1.5 kmph
Speed in DownStream = 6 kmph
Speed in UpStream = 3 kmph
Average Speed = (2 x 6 x 3)/9 = 4 kmph. - 1. 1, 2, 6, 21, 88, 445,?
Options- A. 2230
- B. 2676
- C. 2580
- D. 2670 Discuss
- 2. Divided 124 into four parts which are in AP such that the product of the first and fourth part is 128 less than the products of the seconds and third part?
Options- A. 17, 25, 37, 45
- B. 19, 27, 35, 43
- C. 21, 29, 33, 41
- D. 15, 23, 39, 47 Discuss
- 3. In a geometric progression, the sum of the first and the last terms is 66 and the product of the second and the last second terms is 128. Determine the first term of the series?
Options- A. 64
- B. 64 or 2
- C. 2 or 32
- D. 32 Discuss
- 4. 13, 35, 57, 79, 911,?
Options- A. 1113
- B. 1123
- C. 1114
- D. 1124 Discuss
- 5. In the adjoining figure ?A + ?B + ?C + ?D + ?E + ?F =?
Options- A. 270°
- B. 300°
- C. 360°
- D. 330° Discuss
- 6. If log 2 = 0.3010, then the number of digits in 2 64 is?
Options- A. 18
- B. 19
- C. 20
- D. 21 Discuss
- 7. The value of log 23 x log 32 x log 34 x log 43 is?
Options- A. 1
- B. 2
- C. 3
- D. 4 Discuss
- 8. Find the value of log (a 2 / bc) + log (b 2 / ac) + log (c 2 / ab)?
Options- A. 0
- B. 1
- C. abc
- D. ab2c2 Discuss
- 9. The equation log ax + log a (1+x)=0 can be written as?
Options- A. x2 + x - 1 = 0
- B. x2 + x + 1 = 0
- C. x2 + x - e = 0
- D. x2 + x + e = 0 Discuss
- 10. If log 8 x + log 4 x + log 2x =11, then the value of x is?
Options- A. 2
- B. 4
- C. 8
- D. 64 Discuss
More questions
Correct Answer: 2676
Explanation:
1 x 1 + 1 = 2
2 x 2 + 2 = 6
6 x 3 + 3 = 21
21 x 4 + 4 = 88
88 x 5 + 5 = 445
445 x 6 + 6 = 2676 Should come in place of '?'
Correct Answer: 19, 27, 35, 43
Explanation:
Let the four parts be (a - 3d), (a - d), (a + d) and (a + 3d).
(a - 3d) + (a - d) + (a +d ) + (a + 3d) = 124
? a = 31
Also, (a - 3d) (a + 3d) = (a - d) (a + d) - 128
? a2 - 9d2 = a2 - d2 - 128
? 8d2 = 128
? d = 4
a = 31, d = 4
So, the four parts are 19, 27, 35, 43.
Correct Answer: 64 or 2
Explanation:
Let a be the first term and and r be the common ratio of the GP. From the given problem,
a + arn - 1 = 66 ...(i)
Also, ar x arn - 2 = 128 ? a2rn - 1 = 128 ... (ii)
From Eq. (ii),
a.arn - 1 = 128
arn - 1 = 128/ a
On substitution this in Eq.(i), we get
a + 128/a = 66
a2 - 66a + 128 = 0
a = [-b ± ?b2 - 4ac] /2a
= 66 ± ?662 - 4 x 128 x 1)/2 = 64 or 2
Correct Answer: 1113
Explanation:
Series pattern
The elements of the given series are the numbers formed by joining together consecutive add numbers in order
i.e, 1 and 3, 3 and 5, 5 and 7, 7 and 9, 9 and 11,...
? Missing tern = Number formed by joining 11 and 13 = 1113
Correct Answer: 360°
Explanation:
In ?ACE
?A + ?C + ?E = 180°
Similarly in ?DFB
?D + ?F + ?B = 180°
? (?A + ?C + ?E) + (?D + ?F + ?B) = 360°
?A + ?B + ?C + ?D + ?E + ?F = 360°
Correct Answer: 20
Explanation:
Required answer = [64 log10 2] + 1
= [ 64 x 0.3010 ] + 1
= 19.264 + 1
= 19 + 1
= 20
Correct Answer: 1
Explanation:
Given Exp.= log23 x log 32 x log34 x log43
= (log3 / log2) x ( log2 / log3) x (log4 / log3) x (log3 / log4) = 1
Correct Answer: 0
Explanation:
Given Exp. = log (a2 / bc) + log (b2 / ac) + log (c2 / ab)
= log [(a2 x b2 x c2) / (a2 x b2 x c2)]
=log 1
=0
Correct Answer: x2 + x - 1 = 0
Explanation:
logax + loga(1+x) = 0
? logax (x+1) = loga1 (since log 1 = 0)
? x(x +1) = 1
? x2 + x - 1 = 0
Correct Answer: 64
Explanation:
? log23 x1 +log22 x1 + log2x = 11
? 1/3log2x + 1/2log2x + log2x = 11
? (1/3 + 1/2 +1)log2x = 11
? 11/6log2x = 11
? log2x = 11 x 6 / 11 =6
? x = 26 = 64
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