Discussion
Home ‣ Aptitude ‣ Time and Distance Comments
- Question
Two boys starting from the same place walk at a rate of 5kmph and 5.5kmph respectively. What time will they take to be 8.5km apart, if they walk in the same direction?
Options- A. 15 hours
- B. 16 hours
- C. 17 hours
- D. 18 hours
- Correct Answer
- 17 hours
ExplanationIn this type of questions we need to get the relative speed between them,
The relative speed of the boys = 5.5kmph ? 5kmph
= 0.5 kmph
Distance between them is 8.5 km
Time = Distance/Speed
Time= 8.5km / 0.5 kmph = 17 hrs - 1. P, Q and R start simultaneously from A to B. P reaches B, turns back and meet Q at a distance of 11 km from B. Q reached B, turns back and meet R at a distance of 9 km from B. If the ratio of the speeds of P and R is 3:2, what is the distance between A and B ?
Options- A. 99
- B. 100
- C. 89
- D. 1 Discuss
- 2. Two persons start running simultaneously around a circular track of length 300 m from the same point at speeds of 15 km/hr and 25 km/hr. When will they meet for the first time any where on the track if they are moving in opposite directions ?
Options- A. 27 sec
- B. 31 sec
- C. 23 sec
- D. 29 sec Discuss
- 3. Shahrukh starts from Barabanki to Fatehpur , 1 hour after Ajay starts. Shahrukh meets Kajol 1.5 hours after Shahrukh starts. If the speed of Shahrukh is at least 20km/h faster than the speed of Kajol. What is the minimum speed of Shahrukh to overtake Ajay, before he meets Kajol?
Options- A. 30
- B. 40
- C. 60
- D. None of these Discuss
- 4. Akhil after travelling 50 km meets Raju who suggests him to go slower. He then proceeds at ¾ of his former speed and arrives at his destination 35 minutes late. Had the meeting occurred 24 km further Akhil would have reached its destination 25 minutes late. What is the initial speed of Akhil?
Options- A. 48 kmph
- B. 36 kmph
- C. 24 kmph
- D. 20 kmph Discuss
- 5. A man is riding a bike with front and back wheel circumference of 40 inches and 70 inches respectively. If the man rides the bike on a straight road without slippage, how many inches will the man have travelled when the front wheel has made 15 revolutions more than the back wheel?
Options- A. 1100
- B. 1300
- C. 1400
- D. 1200 Discuss
- 6. A machine puts c caps on bottles in m minutes. How many hours will it take to put caps on b bottles
Options- A. 60bm/c
- B. bm/60c
- C. bc/60m
- D. 60b/cm Discuss
- 7. A son and father goes for boating in river upstream . After rowing for 1 mile son notices the hat of his father falling in the river. After 5 min he tells his father that his hat has fallen. So they turn round and are able to pick the hat at the point from where they began boating after 5min. Find the speed of river in miles/hours ?
Options- A. 4 mile/hr
- B. 6 mile/hr
- C. 2 mile/hr
- D. 5 mile/hr Discuss
- 8. Ashwin fires two bullets from the same place at an interval of 15 minutes but Rahul sitting in a bus approaching the place hears the second sound 14 minutes 30 seconds after the first. If sound travels at the speed of 330 meter per second, what is the approximate speed of bus?
Options- A. 330/29 m/s
- B. 330 x 30 m/s
- C. 330/14 m/s
- D. 330/900 m/s Discuss
- 9. If a girl cycles at 10 kmph, then she arrives at a certain place at 1 p.m. If she cycles at 15 kmph, she will arrive at the same place at 11 a.m. At what speed must she cycle to get there at noon?
Options- A. 14 kmph
- B. 13 kmph
- C. 12 kmph
- D. 11 kmph Discuss
- 10. A man covers a distance of 1200 km in 70 days resting 9 hours a day, if he rests 10 hours a day and walks with speed 1½ times of the previous in how many days will he cover 840 km ?
Options- A. 39 days
- B. 37 days
- C. 35 days
- D. 33 days Discuss
Time and Distance problems
Search Results
Correct Answer: 99
Explanation:
Let, Distance between A and B = d
Distance travelled by P while it meets Q = d + 11
Distance travelled by Q while it meets P = d ? 11
Distance travelled by Q while it meets R = d + 9
Distance travelled by R while it meets Q = d ? 9
Here the ratio of speeds of P & Q => SP : SQ = d + 11 : d ? 11
The ratio of speeds of Q & R => SQ : SR = d + 9 : d ? 9
But given Ratio of speeds of P & R => P : R = 3 : 2
=> = 3/2
=> d = 1, 99
=> d = 99 satisfies.
Therefore, Distance between A and B = 99
Correct Answer: 27 sec
Explanation:
Time taken to meet for the first time anywhere on the track
= length of the track / relative speed
= 300 / (15 + 25)5/18 = 300x 18 / 40 x 5 = 27 seconds.
Correct Answer: None of these
Explanation:
Let t be the time after Kajol starts, when she meets Ajay, then
t = 300/(x+y)
This should be less than 2.5 or (x+y)>120
Since y= 3x/2 => y > 72
This (y>72) is greater than 67.5 km/h and hence Shahrukh will always overtake Ajay before he meets Kajol.
Correct Answer: 48 kmph
Explanation:
Let the initial speed of Akhil be '4p' kmph
Then speed after decrease in speed = '3p' kmph
We know that,
Change in speed == Change in time
According to the given data,
Hence, the initial speed of Akhil = 4p = 4 x 12 = 48 kmph.
Correct Answer: 1400
Explanation:
Given the ratio of the circumference of front wheel is 40 inches and back wheel is 70 inches.
Distance covered = Circumference of the wheel × No. of Revolutions made by the wheel
If n is the number of revolutions made by back wheel, the number of revolutions made by front wheel is n+15
Distance covered by both the wheels is the same
i.e, 40*(n+15)=70n
n=20
Front wheel : Back Wheel
Circumference 40 : 70
Revolutions 35 : 20
Distance covered : 40×35 = 70×20 = 1400 inches.
Correct Answer: bm/60c
Explanation:
Substitute sensible numbers and work out the problem. Then change the numbers back to letters. For example if the machine puts 6 caps on bottles in 2 minutes, it will put 6 /2 caps on per minute, or (6 /2) x 60 caps per hour. Putting letters back this is 60c/m.If you divide the required number of caps (b) by the caps per hour you will get time taken in hours. This gives bm/60c
Correct Answer: 6 mile/hr
Explanation:
Let the speed of river and boat be 'r' m/min and 'b' m/min.
so relative speed in upstream (b-r)m/min and in downstream (b+r)m/min.
Now in upstream distnce covered in 5 min is 5(b-r)miles
so total distnce covered => 1 + 5(b-r)miles in upstream
In downstream distance covered in 5min is 5(b+r)miles
Now 1 + 5(b-r) = 5(b+r)
1+5b-5r = 5b+5r
1 = 10r
r = 1/10 mile/min => 6 mile/hr.
Correct Answer: 330/29 m/s
Explanation:
Second gun shot take 30 sec to reach rahul imples distance between two.
given speed of sound = 330 m/s
Now, distance = 330 m/s x 30 sec
Hence, speed of the bus = d/t = 330x30/(14x60 + 30) = 330/29 m/s.
Correct Answer: 12 kmph
Explanation:
The distance is constant in this case.
Let the time taken for travel with a speed of 10 kmph be 't'.
Now the speed of 15 kmph is 3/2 times the speed of 10 kmph.
Therefore, time taken with the speed of 15 kmph will be 2t/3 (speed is inversely proportional to time)
Extra time taken = t - 2t/3 = t/3
=> 1pm - 11am = 2hrs
=> t/3 = 2h
=> t = 6 hrs.
Now, Distance = speed x time = 10 x 6 = 60 kms
Time he takes to reach at noon = 6 - 1 = 5 hrs
Now, Speed = 60/5 = 12 kmph.
Correct Answer: 35 days
Explanation:
Distance d = 1200km
let S be the speed
he walks 15 hours a day(i.e 24 - 9)
so totally he walks for 70 x 15 = 1050hrs.
S = 1200/1050 => 120/105 = 24/21 => 8/7kmph
given 1 1/2 of previous speed
so 3/2 * 8/7= 24/14 = 12/7
New speed = 12/7kmph
Now he rests 10 hrs a day that means he walks 14 hrs a day.
time = 840 x 7 /12 => 490 hrs
=> 490/14 = 35 days
So he will take 35 days to cover 840 km.
Comments
There are no comments.More in Aptitude:
Programming
Copyright ©CuriousTab. All rights reserved.