Let the time taken by train be 't' hrs.
Then,
40t = 35t + 35/4
t = 7/4 hrs
Therefore, Required length of the total journey d = s x t
= 40 x 7/4
= 70 kms.
Distance to be covered = = km
Relative speed of bikers = 16 + 14 = 30 kmph.
Now, = = 4.18 hrs.
Do not assume that AB and C are on a straight line. Make a diagram with A and B marked 5 miles apart. Draw a circle centered on B, with radius 6. C could be anywhere on this circle. The minimum distance will be 1, and maximum 11
Let the actual distance be t kms
Now, According to the data,
Now, the total distance = 6t = 6 x 2/3 = 2 x 2 = 4 kms.
Average speed =
, here a=25 b=4
= 2 x 25 x 4/(25+4) = 200/29 km/hr.
Distance covered in 5 hours 48 minutes
= Speed x time = (200/29)x (29/5) Distance covered in 5 hours 48 minutes = 40kms.
Distance of the post office from the village = (40/2) = 20 km.
Let x and y be the respective km's travelled by man via taxi and by his own car.
Given x + y = 90 => x = 90 - y
But according to the question,
7x + 6y = 595
7(90-y) + 6y = 595
=> 630 - 7y + 6y = 595
=> y = 630 - 595 = 35
=> x = 90 - 35 = 55
Therefore, the distance travelled by taxi is 55 kms.
Given the ratio of the circumference of front wheel is 40 inches and back wheel is 70 inches.
Distance covered = Circumference of the wheel × No. of Revolutions made by the wheel
If n is the number of revolutions made by back wheel, the number of revolutions made by front wheel is n+15
Distance covered by both the wheels is the same
i.e, 40*(n+15)=70n
n=20
Front wheel : Back Wheel
Circumference 40 : 70
Revolutions 35 : 20
Distance covered : 40×35 = 70×20 = 1400 inches.
Let the initial speed of Akhil be '4p' kmph
Then speed after decrease in speed = '3p' kmph
We know that,
Change in speed == Change in time
According to the given data,
Hence, the initial speed of Akhil = 4p = 4 x 12 = 48 kmph.
Let t be the time after Kajol starts, when she meets Ajay, then
t = 300/(x+y)
This should be less than 2.5 or (x+y)>120
Since y= 3x/2 => y > 72
This (y>72) is greater than 67.5 km/h and hence Shahrukh will always overtake Ajay before he meets Kajol.
Time taken to meet for the first time anywhere on the track
= length of the track / relative speed
= 300 / (15 + 25)5/18 = 300x 18 / 40 x 5 = 27 seconds.
Let, Distance between A and B = d
Distance travelled by P while it meets Q = d + 11
Distance travelled by Q while it meets P = d ? 11
Distance travelled by Q while it meets R = d + 9
Distance travelled by R while it meets Q = d ? 9
Here the ratio of speeds of P & Q => SP : SQ = d + 11 : d ? 11
The ratio of speeds of Q & R => SQ : SR = d + 9 : d ? 9
But given Ratio of speeds of P & R => P : R = 3 : 2
=> = 3/2
=> d = 1, 99
=> d = 99 satisfies.
Therefore, Distance between A and B = 99
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