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- Question
Karthik walks at 5 km/hr and reaches his destination 8 min late. If he walks at 6 km/hr, he reaches his destination on time. What distance he will cover in given time ?
Options- A. 10 kms
- B. 8 kms
- C. 6 kms
- D. 4 kms
- Correct Answer
- 4 kms
ExplanationLet the actual distance be t kms
Now, According to the data,
Now, the total distance = 6t = 6 x 2/3 = 2 x 2 = 4 kms.
- 1. A man traveled from the village to the post-office at the rate of 25 kmph and walked back at the rate of 4 kmph. If the whole journey took 5 hours 48 minutes, find the distance of the post-office from the village ?
Options- A. 40 km
- B. 30 km
- C. 20 km
- D. 10 km Discuss
- 2. An employee may claim Rs. 7.00 for each km when he travels by taxi and Rs. 6.00 for each km if he drives his own car. If in one week he claimed Rs. 595 for traveling 90 km. How many kms did he travel by taxi ?
Options- A. 55 kms
- B. 35 kms
- C. 25 kms
- D. 65 kms Discuss
- 3. A Person X started at 3 hours earlier at 40km/h from a place P, then another person Y followed him at 60km/h. Started his journey at 3 O'clock, afternoon. What is the diference in time when X was30 km ahead of Y and when Y was 30 km ahead of X?
Options- A. 2h
- B. 3h
- C. 3.5h
- D. 4.25h Discuss
- 4. A and B runs around a circular track. A beats B by one round or 10 minutes. In this race, they had completed 4 rounds. If the race was only of one round, find the A's time over the course:
Options- A. 8 min
- B. 7.5 min
- C. 12.5 min
- D. 12 min Discuss
- 5. A man covers half of his journey by train at 60 km/hr, half of the remaining by bus at 30 km/hr and the rest by cycle at 10 km/hr. Find his average speed during the entire journey?
Options- A. 32 kmph
- B. 20 kmph
- C. 18 kmph
- D. 24 kmph Discuss
- 6. The distance from town A to town B is five miles. C is six miles from B. Which of the following could be the maximum distance from A to C?
Options- A. 11
- B. 8
- C. 2
- D. 4 Discuss
- 7. Two bike riders ride in opposite directions around a circular track, starting at the same time from the same point. Biker A rides at a speed of 16 kmph and biker B rides at a speed of 14 kmph. If the track has a diameter of 40 km, after how much time (in hours) will the two bikers meet?
Options- A. 6.52
- B. 8.14
- C. 4.18
- D. 5.02 Discuss
- 8. With an average speed of 40 km/hr, a train reaches its destination in time. If it goes with an average speed of 35 km/hr, it is late by 15 minutes. Find the length of the total journey?
Options- A. 70 kms
- B. 60 kms
- C. 45 kms
- D. 30 kms Discuss
- 9. A man is riding a bike with front and back wheel circumference of 40 inches and 70 inches respectively. If the man rides the bike on a straight road without slippage, how many inches will the man have travelled when the front wheel has made 15 revolutions more than the back wheel?
Options- A. 1100
- B. 1300
- C. 1400
- D. 1200 Discuss
- 10. Akhil after travelling 50 km meets Raju who suggests him to go slower. He then proceeds at ¾ of his former speed and arrives at his destination 35 minutes late. Had the meeting occurred 24 km further Akhil would have reached its destination 25 minutes late. What is the initial speed of Akhil?
Options- A. 48 kmph
- B. 36 kmph
- C. 24 kmph
- D. 20 kmph Discuss
Time and Distance problems
Search Results
Correct Answer: 20 km
Explanation:
Average speed =
, here a=25 b=4
= 2 x 25 x 4/(25+4) = 200/29 km/hr.
Distance covered in 5 hours 48 minutes
= Speed x time = (200/29)x (29/5) Distance covered in 5 hours 48 minutes = 40kms.
Distance of the post office from the village = (40/2) = 20 km.
Correct Answer: 55 kms
Explanation:
Let x and y be the respective km's travelled by man via taxi and by his own car.
Given x + y = 90 => x = 90 - y
But according to the question,
7x + 6y = 595
7(90-y) + 6y = 595
=> 630 - 7y + 6y = 595
=> y = 630 - 595 = 35
=> x = 90 - 35 = 55
Therefore, the distance travelled by taxi is 55 kms.
Correct Answer: 3h
Explanation:
Time ( when X was 30 km ahead of Y) = (120-30)/20 =4.5h
Time ( when Y was 30 km ahead of X) = (120+30)/20 = 7.5 h
Thus, required difference in time = 3h
Correct Answer: 7.5 min
Explanation:
B runs around the track in 10 min.
i.e , Speed of B = 10 min per round
Therefore, A beats B by 1 round
Time taken by A to complete 4 rounds
= Time taken by B to complete 3 rounds
= 30 min
Therefore, A's speed = 30/4 min per round = 7.5 min per round
Hence, if the race is only of one round A's time over the course = 7 min 30 sec
Correct Answer: 24 kmph
Explanation:
Let the total distance of the journey of a man = d kms
Now, the average speed of the entire journey = = 24 kmph.
Correct Answer: 11
Explanation:
Do not assume that AB and C are on a straight line. Make a diagram with A and B marked 5 miles apart. Draw a circle centered on B, with radius 6. C could be anywhere on this circle. The minimum distance will be 1, and maximum 11
Correct Answer: 4.18
Explanation:
Distance to be covered = = km
Relative speed of bikers = 16 + 14 = 30 kmph.
Now, = = 4.18 hrs.
Correct Answer: 70 kms
Explanation:
Let the time taken by train be 't' hrs.
Then,
40t = 35t + 35/4
t = 7/4 hrs
Therefore, Required length of the total journey d = s x t
= 40 x 7/4
= 70 kms.
Correct Answer: 1400
Explanation:
Given the ratio of the circumference of front wheel is 40 inches and back wheel is 70 inches.
Distance covered = Circumference of the wheel × No. of Revolutions made by the wheel
If n is the number of revolutions made by back wheel, the number of revolutions made by front wheel is n+15
Distance covered by both the wheels is the same
i.e, 40*(n+15)=70n
n=20
Front wheel : Back Wheel
Circumference 40 : 70
Revolutions 35 : 20
Distance covered : 40×35 = 70×20 = 1400 inches.
Correct Answer: 48 kmph
Explanation:
Let the initial speed of Akhil be '4p' kmph
Then speed after decrease in speed = '3p' kmph
We know that,
Change in speed == Change in time
According to the given data,
Hence, the initial speed of Akhil = 4p = 4 x 12 = 48 kmph.
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