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- Question
A and B runs around a circular track. A beats B by one round or 10 minutes. In this race, they had completed 4 rounds. If the race was only of one round, find the A's time over the course:
Options- A. 8 min
- B. 7.5 min
- C. 12.5 min
- D. 12 min
- Correct Answer
- 7.5 min
ExplanationB runs around the track in 10 min.
i.e , Speed of B = 10 min per round
Therefore, A beats B by 1 round
Time taken by A to complete 4 rounds
= Time taken by B to complete 3 rounds
= 30 min
Therefore, A's speed = 30/4 min per round = 7.5 min per round
Hence, if the race is only of one round A's time over the course = 7 min 30 sec
- 1. A man covers half of his journey by train at 60 km/hr, half of the remaining by bus at 30 km/hr and the rest by cycle at 10 km/hr. Find his average speed during the entire journey?
Options- A. 32 kmph
- B. 20 kmph
- C. 18 kmph
- D. 24 kmph Discuss
- 2. If Deepesh had walked 20 km/h faster he woulh have saved 1 hour in the distance of 60km. what is the usual speed of Deepesh?
Options- A. 100
- B. 120
- C. 150
- D. None of these Discuss
- 3. A man in a train notices that he can count 41 telephone posts in one minute. If they are known to be 50 metres apart, then at what speed is the train travelling?
Options- A. 60 km/hr
- B. 100 km/hr
- C. 110 km/hr
- D. 120 km/hr Discuss
- 4. A man reaches his office 20 min late, if he walks from his home at 3 km per hour and reaches 30 min early if he walks 4 km per hour. How far is his office from his house ?
Options- A. 20 km
- B. 16 km
- C. 14 km
- D. 10 km Discuss
- 5. A train covers a distance in 50 minutes, if it runs at a speed of 48kmph on an average. Find the speed at which the train must run to reduce the time of journey to 40 minutes.
Options- A. 50 km/hr
- B. 60 km/hr
- C. 65 km/hr
- D. 70 km/hr Discuss
- 6. A Person X started at 3 hours earlier at 40km/h from a place P, then another person Y followed him at 60km/h. Started his journey at 3 O'clock, afternoon. What is the diference in time when X was30 km ahead of Y and when Y was 30 km ahead of X?
Options- A. 2h
- B. 3h
- C. 3.5h
- D. 4.25h Discuss
- 7. An employee may claim Rs. 7.00 for each km when he travels by taxi and Rs. 6.00 for each km if he drives his own car. If in one week he claimed Rs. 595 for traveling 90 km. How many kms did he travel by taxi ?
Options- A. 55 kms
- B. 35 kms
- C. 25 kms
- D. 65 kms Discuss
- 8. A man traveled from the village to the post-office at the rate of 25 kmph and walked back at the rate of 4 kmph. If the whole journey took 5 hours 48 minutes, find the distance of the post-office from the village ?
Options- A. 40 km
- B. 30 km
- C. 20 km
- D. 10 km Discuss
- 9. Karthik walks at 5 km/hr and reaches his destination 8 min late. If he walks at 6 km/hr, he reaches his destination on time. What distance he will cover in given time ?
Options- A. 10 kms
- B. 8 kms
- C. 6 kms
- D. 4 kms Discuss
- 10. The distance from town A to town B is five miles. C is six miles from B. Which of the following could be the maximum distance from A to C?
Options- A. 11
- B. 8
- C. 2
- D. 4 Discuss
Time and Distance problems
Search Results
Correct Answer: 24 kmph
Explanation:
Let the total distance of the journey of a man = d kms
Now, the average speed of the entire journey = = 24 kmph.
Correct Answer: 100
Explanation:
Let the original speed be x km/h, then
Therefore, original speed = 100km/h
Correct Answer: 120 km/hr
Explanation:
Number of gaps between 41 poles = 40
So total distance between 41 poles = 40*50
= 2000 meter = 2 km
In 1 minute train is moving 2 km/minute.
Speed in hour = 2*60 = 120 km/hour
Correct Answer: 10 km
Explanation:
Let distance = x km.
Time taken at 3 kmph : dist/speed = x/3 = 20 min late.
time taken at 4 kmph : x/4 = 30 min earlier
difference between time taken : 30-(-20) = 50 mins = 50/60 hours.
x/3- x/4 = 50/60
x/12 = 5/6
x = 10 km.
Correct Answer: 60 km/hr
Explanation:
We are having time and speed given, so first we will calculate the distance. Then we can get new speed for given time and distance.
Lets solve it.
Time = 50/60 hr = 5/6 hr
Speed = 48 mph
Distance = S*T = 48 * 5/6 = 40 km
New time will be 40 minutes so,
Time = 40/60 hr = 2/3 hr
Now we know,
Speed = Distance/Time
New speed = 40*3/2 kmph = 60kmph
Correct Answer: 3h
Explanation:
Time ( when X was 30 km ahead of Y) = (120-30)/20 =4.5h
Time ( when Y was 30 km ahead of X) = (120+30)/20 = 7.5 h
Thus, required difference in time = 3h
Correct Answer: 55 kms
Explanation:
Let x and y be the respective km's travelled by man via taxi and by his own car.
Given x + y = 90 => x = 90 - y
But according to the question,
7x + 6y = 595
7(90-y) + 6y = 595
=> 630 - 7y + 6y = 595
=> y = 630 - 595 = 35
=> x = 90 - 35 = 55
Therefore, the distance travelled by taxi is 55 kms.
Correct Answer: 20 km
Explanation:
Average speed =
, here a=25 b=4
= 2 x 25 x 4/(25+4) = 200/29 km/hr.
Distance covered in 5 hours 48 minutes
= Speed x time = (200/29)x (29/5) Distance covered in 5 hours 48 minutes = 40kms.
Distance of the post office from the village = (40/2) = 20 km.
Correct Answer: 4 kms
Explanation:
Let the actual distance be t kms
Now, According to the data,
Now, the total distance = 6t = 6 x 2/3 = 2 x 2 = 4 kms.
Correct Answer: 11
Explanation:
Do not assume that AB and C are on a straight line. Make a diagram with A and B marked 5 miles apart. Draw a circle centered on B, with radius 6. C could be anywhere on this circle. The minimum distance will be 1, and maximum 11
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