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- Question
A man reaches his office 20 min late, if he walks from his home at 3 km per hour and reaches 30 min early if he walks 4 km per hour. How far is his office from his house ?
Options- A. 20 km
- B. 16 km
- C. 14 km
- D. 10 km
- Correct Answer
- 10 km
ExplanationLet distance = x km.
Time taken at 3 kmph : dist/speed = x/3 = 20 min late.
time taken at 4 kmph : x/4 = 30 min earlier
difference between time taken : 30-(-20) = 50 mins = 50/60 hours.
x/3- x/4 = 50/60
x/12 = 5/6
x = 10 km. - 1. A train covers a distance in 50 minutes, if it runs at a speed of 48kmph on an average. Find the speed at which the train must run to reduce the time of journey to 40 minutes.
Options- A. 50 km/hr
- B. 60 km/hr
- C. 65 km/hr
- D. 70 km/hr Discuss
- 2. Amy has to visit towns B and C in any order. The roads connecting these towns with her home are shown on the diagram. How many different routes can she take starting from A and returning to A, going through both B and C (but not more than once through each) and not travelling any road twice on the same trip?
Options- A. 10
- B. 8
- C. 6
- D. 4 Discuss
- 3. The ratio between the speeds of two trains is 7: 8. If the second train runs 400 kms in 4 hours, then the speed of the first train is ?
Options- A. 83.5 km/hr
- B. 84.5 km/hr
- C. 86.5 km/hr
- D. 87.5 km/hr Discuss
- 4. The number of degrees that the hour hand of a clock moves through between noon and 2.30 in the afternoon of the same day is
Options- A. 720
- B. 180
- C. 75
- D. 65 Discuss
- 5. A train with 120 wagons crosses Arun who is going in the same direction, in 36 seconds. It travels for half an hour from the time it starts overtaking the Arun ( he is riding on the horse) before it starts overtaking the Sriram( who is also riding on his horse) coming from the opposite direction in 24 seconds. In how much time (in seconds) after the train has crossed the Sriram do the Arun meets to Sriram?
Options- A. 3560 sec
- B. 3600 sec
- C. 3576 sec
- D. can't be determined Discuss
- 6. A man in a train notices that he can count 41 telephone posts in one minute. If they are known to be 50 metres apart, then at what speed is the train travelling?
Options- A. 60 km/hr
- B. 100 km/hr
- C. 110 km/hr
- D. 120 km/hr Discuss
- 7. If Deepesh had walked 20 km/h faster he woulh have saved 1 hour in the distance of 60km. what is the usual speed of Deepesh?
Options- A. 100
- B. 120
- C. 150
- D. None of these Discuss
- 8. A man covers half of his journey by train at 60 km/hr, half of the remaining by bus at 30 km/hr and the rest by cycle at 10 km/hr. Find his average speed during the entire journey?
Options- A. 32 kmph
- B. 20 kmph
- C. 18 kmph
- D. 24 kmph Discuss
- 9. A and B runs around a circular track. A beats B by one round or 10 minutes. In this race, they had completed 4 rounds. If the race was only of one round, find the A's time over the course:
Options- A. 8 min
- B. 7.5 min
- C. 12.5 min
- D. 12 min Discuss
- 10. A Person X started at 3 hours earlier at 40km/h from a place P, then another person Y followed him at 60km/h. Started his journey at 3 O'clock, afternoon. What is the diference in time when X was30 km ahead of Y and when Y was 30 km ahead of X?
Options- A. 2h
- B. 3h
- C. 3.5h
- D. 4.25h Discuss
Time and Distance problems
Search Results
Correct Answer: 60 km/hr
Explanation:
We are having time and speed given, so first we will calculate the distance. Then we can get new speed for given time and distance.
Lets solve it.
Time = 50/60 hr = 5/6 hr
Speed = 48 mph
Distance = S*T = 48 * 5/6 = 40 km
New time will be 40 minutes so,
Time = 40/60 hr = 2/3 hr
Now we know,
Speed = Distance/Time
New speed = 40*3/2 kmph = 60kmph
Correct Answer: 8
Explanation:
Amy can travel clockwise or anticlockwise on the diagram.
Clockwise, she has no choice of route from A to B, a choice of one out of two routes from B to C, and a choice of one out of two routes from C back to A. This gives four possible routes.
Similarly, anticlockwise she has four different routes.
Total routes = 8
Correct Answer: 87.5 km/hr
Explanation:
Let the speeds of two trains be 7X and 8X km/hr.
8x = 400/4
=> x= 12.5 km/hrX=4004=>X=12.5Km/hr
So speed of first train is 12.5*7 = 87.5 km/hr
Correct Answer: 75
Explanation:
The hour hand moves from pointing to 12 to pointing to half way between 2 and 3. The angle covered between each hour marking on the clock is 360/12 = 30. Since the hand has covered 2.5 of these divisions the angle moved through is 75.
Correct Answer: 3576 sec
Explanation:
Let the length of the train be L metres and speeds of the train Arun and Sriram be R, A and S respectively, then
---------- (i)
and ---------(ii)
From eq.(i) and (ii)
3(R - A ) = 2 (R + K)
R = 3A + 2K
In 30 minutes (i.e 1800 seconds), the train covers 1800R (distance) but the Arun also covers 1800 A (distance) in the same time. Therefore distance between Arun and Sriram, when the train has just crossed Sriram
= 1800 ( R - A) - 24 ( A + K)
Time required =
= (3600 - 24) = 3576 s
Correct Answer: 120 km/hr
Explanation:
Number of gaps between 41 poles = 40
So total distance between 41 poles = 40*50
= 2000 meter = 2 km
In 1 minute train is moving 2 km/minute.
Speed in hour = 2*60 = 120 km/hour
Correct Answer: 100
Explanation:
Let the original speed be x km/h, then
Therefore, original speed = 100km/h
Correct Answer: 24 kmph
Explanation:
Let the total distance of the journey of a man = d kms
Now, the average speed of the entire journey = = 24 kmph.
Correct Answer: 7.5 min
Explanation:
B runs around the track in 10 min.
i.e , Speed of B = 10 min per round
Therefore, A beats B by 1 round
Time taken by A to complete 4 rounds
= Time taken by B to complete 3 rounds
= 30 min
Therefore, A's speed = 30/4 min per round = 7.5 min per round
Hence, if the race is only of one round A's time over the course = 7 min 30 sec
Correct Answer: 3h
Explanation:
Time ( when X was 30 km ahead of Y) = (120-30)/20 =4.5h
Time ( when Y was 30 km ahead of X) = (120+30)/20 = 7.5 h
Thus, required difference in time = 3h
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