Dividend on Rs. 20 = Rs. (9/100)x 20 = Rs.9/5.
Rs. 12 is an income on Rs. 100.
Rs.9/5 is an income on Rs.[ (100/12) x (9/5)] = Rs. 15.
From the information provided we know that,
Principal + 8% p.a. interest on principal for n years = 180 ??.. (1)
Principal + 4% p.a. interest on principal for n years = 120 ??? (2)
Subtracting equation (2) from equation (1), we get
4% p.a. interest on principal for n years = Rs.60.
Now, we can substitute this value in equation (2),
i.e Principal + 60 = 120
= Principal = Rs.60.
We know that SI = , where p is the principal, n the number of years and r the rate percent of interest.
In equation (2), p = Rs.60, r = 4% p.a. and the simple interest = Rs.60.
Therefore, 60 =(60*n*4)/100
=> n = 100/4 = 25 years.
SP2 = 2/3 SP1
CP = 100
SP2 = 80
2/3 SP1 = 80
SP1 = 120
100 --- 20 => 20%
Volume of water collected in the tank in 1 hour
? (0.3 × 0.2 × 20km × 1000mts) = 1200 m cubic
If after t hours, the water is at height of 12m,
1200t=200×150×12
? t = 300 Hours.
Capacity of the tank =(12 x 13.5) liters =162 liters.
Capacity of each bucket =9 liters
Number of buckets needed = 162/9 =18.
Part filled by (A + B) in 1 minute = (1/60 + 1/40) = 1/24
Suppose the tank is filled in x minutes.
Then, x/2(1/24 + 1/40) = 1
(x/2) * (1/15) = 1 => x = 30 min.
SP of first article = Rs.1000
Profit = 20%
SP of Second Article = Rs.1000
Loss = 20%
So, Total SP = Rs.2000; Total CP = Rs.6250/3
As the CP is more than SP, he makes a loss.
Loss = CP - SP = (6250/3) - 2000 = Rs.(250/3)
So, Loss Percent = Lossx100/CP = 4%
Let sum be Rs.x then, S.I. =Rs. [ x * (27/2) * 4 * (1/100) ] = Rs. 27x/50
Amount =Rs [ x + (27x/50)] = Rs.77x/50
=> 77X/50 = 2502.50
=>X= (2502.50 * 50)/77 = 1625
Hence Sum = Rs.1625
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