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Home Aptitude Simplification Comments

  • Question
  • If sec2A cosec2A = x , then x is


  • Options
  • A. sec2A + cosec2A + 2
  • B. tan2A + cot2A - 2
  • C. tan2A + cot2A + 2
  • D. sec2A + cosec2A - 2

  • Correct Answer
  • tan2A + cot2A + 2 

  • Tags: Bank Exams

    Simplification problems


    Search Results


    • 1. What is the value of [cos (90 + A)÷sec (270 ? A)] + [sin (270 + A)÷cosec (630 ? A)]?

    • Options
    • A. 3 sec A
    • B. tan A sec A
    • C. 0
    • D. 1
    • Discuss
    • 2. What is the value of sin (90° + 2A)[4 ? cos2(90° ? 2A)]?

    • Options
    • A. 2(cos3 A ? sin3 A)
    • B. 2(cos3 A + sin3 A)
    • C. 4(cos6 A+ sin6 A)
    • D. 4(cos6 A ? sin6 A)
    • Discuss
    • 3. What is the value of [2 sin (45 + ?) sin (45 ? ?)]/cos 2??

    • Options
    • A. 0
    • B. tan 2?
    • C. cot 2?
    • D. 1
    • Discuss
    • 4. What is the value of [(cos 3? + 2cos 5? + cos 7?)÷(cos ? + 2cos 3? + cos 5?)] + sin 2? tan 3??

    • Options
    • A. cos 2?
    • B. sin 2?
    • C. tan 2?
    • D. cot ? sin 2?
    • Discuss
    • 5. What is the value of sin 75°+ sin 15° ?

    • Options
    • A. ?3
    • B. 2?3
    • C. ?(3/2)
    • D. 3/?2
    • Discuss
    • 6. If sin ?/6 + sec ?/6 = x, then x is

    • Options
    • A. (2?2-1)/2
    • B. 5/?3
    • C. (?6-1)/?2
    • D. (?3+4)/2?3
    • Discuss
    • 7. Square of (3x ? 5xy) is

    • Options
    • A. 9x2 - 30x2y + 25x2y2
    • B. 9x2 - 15x2y + 25x2y2
    • C. 25x2 - 15x2y + 9x2y2
    • D. 25x2 - 30x2y + 9x2y2
    • Discuss
    • 8. If 5 - 2x ? 4 - x and 3(2 - x) > 2 - 4x; then x can take which of the following values?

    • Options
    • A. 3
    • B. 2
    • C. -3
    • D. -5
    • Discuss
    • 9. If x3 = 62 - 32 , then the value of x is

    • Options
    • A. 9
    • B. 6
    • C. 3
    • D. 1
    • Discuss
    • 10. Which of the following is not a quadratic equation?

    • Options
    • A. 2x(x + 4) -11 = x(x - 3) + 6
    • B. 4x(x + 4) -11 = 5x(x - 3) + 5
    • C. x(x + 2) -15 = x(x - 5) + 11
    • D. 2x2 + 8x - 11 = 0
    • Discuss


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