= | ❨ | 66 x | 5 | ❩m/sec |
18 |
= | ❨ | 55 | ❩m/sec. |
3 |
∴ Time taken to pass the man = | ❨ | 110 x | 3 | ❩sec = 6 sec. |
55 |
Speed = | ❨ | 60 x | 5 | ❩m/sec | = | ❨ | 50 | ❩m/sec. |
18 | 3 |
Length of the train = (Speed x Time).
∴ Length of the train = | ❨ | 50 | x 9 | ❩m = 150 m. |
3 |
Principal |
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= Rs. 8925. |
S.I. for 5 years = Rs. | ❨ | 2205 | x 5 | ❩ | = Rs. 3675 |
3 |
∴ Principal = Rs. (9800 - 3675) = Rs. 6125.
Hence, rate = | ❨ | 100 x 3675 | ❩% | = 12% |
6125 x 5 |
Then, | ❨ | x x 14 x 2 | ❩ | + | ❨ | (13900 - x) x 11 x 2 | ❩ | = 3508 |
100 | 100 |
⟹ 28x - 22x = 350800 - (13900 x 22)
⟹ 6x = 45000
⟹ x = 7500.
So, sum invested in Scheme B = Rs. (13900 - 7500) = Rs. 6400.
Speed = | ❨ | 78 x | 5 | ❩ | m/sec | = | ❨ | 65 | ❩ | m/sec. |
18 | 3 |
Time = 1 minute = 60 seconds.
Let the length of the tunnel be x metres.
Then, | ❨ | 800 + x | ❩ | = | 65 |
60 | 3 |
⟹ 3(800 + x) = 3900
⟹ x = 500.
Distance covered by A in x hours = 20x km.
Distance covered by B in (x - 1) hours = 25(x - 1) km.
∴ 20x + 25(x - 1) = 110
⟹ 45x = 135
⟹ x = 3.
So, they meet at 10 a.m.
Then, | ❨ | 5000 x R x 2 | ❩ | + | ❨ | 3000 x R x 4 | ❩ | = 2200. |
100 | 100 |
⟹ 100R + 120R = 2200
⟹ R = | ❨ | 2200 | ❩ | = 10. |
220 |
∴ Rate = 10%.
S.I. for first 6 months = Rs. | ❨ | 100 x 10 x 1 | ❩ | = Rs. 5 |
100 x 2 |
S.I. for last 6 months = Rs. | ❨ | 105 x 10 x 1 | ❩ | = Rs. 5.25 |
100 x 2 |
So, amount at the end of 1 year = Rs. (100 + 5 + 5.25) = Rs. 110.25
∴ Effective rate = (110.25 - 100) = 10.25%
Then, 3(y - x) = (2y - x) ⟹ y = 2x.
Profit = Rs. (y - x) = Rs. (2x - x) = Rs. x.
∴ Profit % = | ❨ | x | x 100 | ❩% = 100% |
x |
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