Here, n = 3, m = 2, T1 = 20 yr
? T2 = [(m -1) / (n - 1)] x T1
= (2 - 1) / (3 - 1) x 20 = 10 yr
So, the missing number = 61 x 2 = 122.
Then, (60 - x) - 6 = 5(x - 6)
⟹ 54 - x = 5x - 30
⟹ 6x = 84
⟹ x = 14.
∴ Son's age after 6 years = (x+ 6) = 20 years..
P.W. of Rs. 12,880 due 8 months hence |
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= Rs. 11500. |
Let the amount be ? a
According to the question,
a x 5/12= 33/4 x 100
? 5a/12 = 15/4 x 100
? a = 12/5 x 15/4 x 100
? a = 12 x 15 x 100/4 x 5
? a = ? 900
Clearly, 7x2 = 49 or 7x2 - 49 = 0, which is of the form ax2 + bx + c = 0, where b = 0.
Thus, 7x2 - 49 = 0 is a quadratic equation.
1 |
4 |
1 |
10 |
7 |
15 |
8 |
15 |
8 |
15 |
Explanation:
A's 1 day's work = | 1 | ; |
15 |
B's 1 day's work = | 1 | ; |
20 |
(A + B)'s 1 day's work = | ❨ | 1 | + | 1 | ❩ | = | 7 | . |
15 | 20 | 60 |
(A + B)'s 4 day's work = | ❨ | 7 | x 4 | ❩ | = | 7 | . |
60 | 15 |
Therefore, Remaining work = | ❨ | 1 - | 7 | ❩ | = | 8 | . |
15 | 15 |
Less spiders, More days (Indirect Proportion)
Less webs, Less days (Direct Proportion)
Spiders | 1 | : | 7 | ] | :: 7 : x |
Webs | 7 | : | 1 |
∴ 1 x 7 x x = 7 x 1 x 7
⟹ x = 7.
Let the speed of the train be V
According to the question.
(V + 10) x 12 = (V + 20) x 10
? 6V + 60 = 5V + 100
? x = 100 - 60 = 40 m/s
? Length of the train = (V + 10) x 12
= (40 + 10) x 12 = 600 m
Then, pipes B and C will take | x | and | x | hours respectively to fill the tank. |
2 | 4 |
∴ | 1 | + | 2 | + | 4 | = | 1 |
x | x | x | 5 |
⟹ | 7 | = | 1 |
x | 5 |
⟹ x = 35 hrs.
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