5358 x 51 = 5358 x (50 +1 )
5358 x 50 + 5358 x 1
=267900 + 5358 = 273258
Total number of cases = 10c4
Favorable number of cases = 4c2. 6c2
{Since, we are to select 2 children out of 4 and remaining 2 persons are to be selected from remaining 6 persons ( 2W + 4M)}
? required Probability = 4c2 . 6c2 / 10c4
= [{(4 x 3) / (2 x 1)} x {(6 x 5) / (2 x 1)}] / [ (10 x 9 x 8 x 7) / (4 x 3 x 2 x 1)]
= [(12/2) x (30/2)] / 210
= 90 / 210
= 9 /12
Let son's age 1 year ago be x years.
? Father's age 1 year ago = 4x years
? 4x + 7 = 2(x + 7) + 9
? 2x = 23 - 7
? x = 8
Ratio of father's and son's present ages = (4x + 1) : (x + 1) = 33 : 9 = 11 : 3
Let A's age be x years, B's age be 2x years and C's age = (x + 17) years
According to the question,
? x + 2x + (x + 17) = 185
? 4x = 185 - 17 = 168
? x = 42
? A's age = 42 years
B's age 84 years
C's age = 42 + 17 = 59 years
Clearly, B covers 18 m in 9 s.
? B's time over the course = 9/18 x 1000 = 500 s
? A' s time over the course = (500 - 9) = 491 s
Let the present age of Ramesh be 3x years and the present age of jayesh = 2x years.
According to question, (3x - 4) = (2x - 4) + 6
? 3x - 4 = 2x - 4 + 6
? 3x - 4 = 2x + 2
? 3x - 2x = 2 + 4
? x = 6
? Present age of Jayesh = 2x = 12 years
Number of possible cases = 100 x 100 for 7m + 7n to be divisible by 5,
One of the term has to end with 9 and other with 1 (7m cannot be divided by 9 )
? m can be 2, 6 , 10, 14, ..... 98 (25 values) and n can be 4, 8, 12 ...... 100(25 values)
Since m and n can interchange
? Required probability = (2 x 25 x 25) / (100 x 100) = 1/8
The probability that head is show in one coin is 1/2.
The probability that the sum of the number on the dice is a prime = the probability that the following pair of number on the dice is a getting on the dice, namely (1, 1), (1, 2), (2, 1), (1, 4 ), (4, 1), (2, 3), (3, 2), (1, 6), (6, 1), (2, 5), (5, 2), (3, 4), (4, 3), (6, 5), (5, 6) = 15/36.
? The required probability = 1/2 x 1/2 x 15/36 = 5/48.
Let the present ages of mother and her daughter are ( x + 25 ) and x years respectively ; then 6( x - 5 ) = x + 25 - 5 ? 6x - 30 = x + 20 ? 5x = 50 ? x = 10
Hence, the age of the mother = 10 + 25 = 35 years
Let us assume x years ago, the ratio of their ages was 3 : 5, then
According to question,
(40 - x)/(60 - x) = 3/5
? (40 - x) 5 = 3 (60 - x)
? 200 - 5x = 180 - 3x
? 2x = 20
? x = 10 years
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