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- Question
Point P is the midpoint of segment AB. Co-ordinates of P are (5, -1) and A are (2, -4). What are the co-ordinates of point B?
Options- A. (6, 4)
- B. (8, 2)
- C. (1,-2)
- D. (-6, -2)
- Correct Answer
- (8, 2)
- 1. What will be the approximate compound interest on Rs. 101005 at 10% p.a. for 3 years?
Options- A. Rs. 4500
- B. Rs. 3000
- C. Rs. 3300
- D. Rs. 3600 Discuss
- 2. Find the cash realised by selling Rs. 2440, 9.5% stock at 4 discount (brokerage 1/4 %)
Options- A. 2000
- B. 2298
- C. 2290
- D. 2289 Discuss
- 3. A moneylender lends Rs. 2000 for 6 months at 20% per annum whereas the interest is compounded quarterly. After the given period he will get the amount of?
Options- A. Rs. 2205
- B. Rs. 2200
- C. Rs. 2160
- D. Rs. 2040 Discuss
- 4. In what time will Rs. 6250 amount to Rs. 6632.55 at 4% compound interest payable half yearly?
Options- A. 3 years
- B. 3/2 years
- C. 1 years
- D. 5/2 years Discuss
- 5. Find the effective annual rate of 5 per cent per annum compound interest paid half yearly?
Options- A. 1.025%
- B. 6.0625%
- C. 5.062%
- D. None of these Discuss
- 6. At what rate of compound interest per annum will a sum of Rs. 1200 become Rs. 1348.32 in 2 years?
Options- A. 7%
- B. 7.5%
- C. 6%
- D. 6.5% Discuss
- 7. A sum of ? 2400 deposited at CI, Double after 5 yr. After 20 yr it will become?
Options- A. ? 24000
- B. ? 38400
- C. ? 19200
- D. Cannot be determined Discuss
- 8. Rohit earns an interest of ? 1656 for the third year and ? 1440 for the second year on the same sum. Find the rate of interest if it is lent at compound interest?
Options- A. 18%
- B. 12%
- C. 15%
- D. None of these Discuss
- 9. What will be the present worth of ? 169 due in 2 yr at 4 % pa compound interest?
Options- A. ? 156.25
- B. ? 160
- C. ? 150.50
- D. ? 154.75 Discuss
- 10. A sum amounts to ? 2916 in 2 yr and ? 3149.28 in 3 yr at compound interest. The sum is?
Options- A. ? 1500
- B. ? 2500
- C. ? 2000
- D. ? 3000 Discuss
More questions
Correct Answer: Rs. 3300
Explanation:
Compound interest = P {(1 + r/100)t - 1}
= 10105 { (1 +10/100)3 - 1}
=10105 {(11/10)3 - 1}
=10105 {1331/1000 - 1}
=10105(331/1000)
= 3344.755
= Rs. 3300(app.)
Correct Answer: 2298
Explanation:
By selling Rs. 100 stock , cash realised =
By selling Rs. 2400 stock, cash realised = = Rs 2298.
Correct Answer: Rs. 2205
Explanation:
For the quarterly interest,
Time = (6/12) year x 4 = 2 quarterly
Rate = 20/4 = 5%
(? On quarterly interest time is multiplied by 4 and rate is divided by 4)
Hence,required amount = Principal (1 + Rate/100)Time
= 2000(1 +5/10)2
= 2000(21/20)2
= Rs. 2205
Correct Answer: 3/2 years
Explanation:
Since Interest accumulates half yearly so effective rate = R/2 = 4/2 = 2.
And effective time is 2t.
? 6250 [1 + 2/100]2t = 6632.55
? (1 +2/100)2t = 663255/625000 = 132651/125000 = (51/50)3
? (51/50)2t = (51/50)3
? 2t =3
? t = 3/2 years
Correct Answer: 5.062%
Explanation:
The amount of Rs. 100 in one year at compound interest at 5% per annum payable half yearly.
= Rs. 100(1 + 5/2 /100)2
=Rs. 100(102.5/100)2
=Rs. 100(1.025)2
=Rs. 105.0625
Thus, the nominal rate of 5% payable half yearly has the same effect as the rate of 5.0625 per cent would have, if payable yearly.
Hence 5.0625 per cent is called the effective annual rate 5% per annum payable half yearly.
Correct Answer: 6%
Explanation:
Let the rate be R% per annum.
Then,
1200 x (1 + R/100)2 = 1348.32
? (1 + R/100)2 =1348.32/1200 = 1.1236 = (1.06)2
? (1 + R/100) =1.06
? R/100 = 0.06
? R = 6%
Correct Answer: ? 38400
Explanation:
2P = P (1 + R/100) 5
? 24 P = P(1 + R/100)20
? The amount becomes 24 times
= 16 times and required amount = 2400 x 16 = ? 38400
Correct Answer: 15%
Explanation:
Interest on ? 1440 = ? 216 for the third year
? Rate percentage = (216 x 100)/(1440 x 1) = 15 %
Correct Answer: ? 156.25
Explanation:
Given R = 4 %, n = 2 yr and A = ? 169.
P = ?
Amount = P(1 + R/100)n
? 169 = P(1 + 4/100 )2
? 169 = P(26/25)2
? P = 169 x (25 x 25)/(26 x 26)
? P = 105625 / 676
= ? 156.25
Correct Answer: ? 2500
Explanation:
Let required amount be ? P.
According to the question,
2916 = P (1 + R/100)2 ... (i)
and 3149.28 = P(1 + R/100)3 ... (ii)
On dividing Eq. (ii) by Eq. (i), we get
1 + R/100 = 3149.28/2916
? R/100 = (3149.28/2916) - 1
? R = (233.28/2916) x 100 = 8%
From Eq. (i),
P = (2916 x 100 x 100)/(108 x 108)
= ? 2500
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