Let two consecutive odd number be (A + 1) and (A + 3).
According to the question.
(A + 1) (A + 3) = 6723
? A2 + 3A + A + 3 = 6723
? A2 + 4A + 3 - 6723 = 0
? A2 + 4A - 6720 = 0
? A2 + 84A - 80A - 6720 = 0
? A(A + 84) - 80 (A + 84) = 0
? (A - 80) (A + 84) = 0
? A = 80, (A = ? - 84)
Hence, the greater number = 80 + 3 = 83
( A + B + C ) / 3 = 11111 ....(i)
Also, ( A+C ) / 2 = 11111 ....(ii)
From Eqs. (i) & (ii), we get
B = ? 11111 crore
? x = 264
? log x = log 264
? log x = 64 log 2
= 64 x .3010 = 19.264
? No.of digits = 19 + 1 = 20
36800 - 9999 - 3333 - 66 = 36800 - ( 9999 - 3333 - 66)
= 36800 - 13398
= 23402
Angle traced by the hour hand in 6 hours = | ❨ | 360 | x 6 | ❩ | ° | = 180°. |
12 |
Relative speed of the train
= (70 - 10)
= 60 km/hr
= (60 x 5/18)
= 50/3) m/sec.
? Time taken by the train to pass the man
= (100 x 3/50) = 6 sec.
Then, quantity of wine left in cask after 4 operations = | [ | x | ❨ | 1 - | 8 | ❩ | 4 | ] litres. |
x |
∴ | ❨ | x(1 - (8/x))4 | ❩ | = | 16 |
x | 81 |
⟹ | ❨ | 1 - | 8 | ❩ | 4 | = | ❨ | 2 | ❩ | 4 |
x | 3 |
⟹ | ❨ | x - 8 | ❩ | = | 2 |
x | 3 |
⟹ 3x - 24 = 2x
⟹ x = 24.
7.2 kg = 7.2 x 1000000 gm = 7200000 gms
Required percentage = (18/7200000) x 100 % = 0.25%
In 19683, 19 lies between 23 and 33, so left digit is 2 and 683 ends with 3, so right digit is 7.
thus 27 is a cube root of 19683.
Area of the field =1215/135 = 9 hec
= 90000 m2 [1 hec =10000 m2]
? Side of the field = ?90000 = 300 m
Perimeter of the field = 4 x 300 = 1200 m
Now, cost of putting a fence around field = (1200 x 75)/100 = ? 900
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