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  • Question
  • Two equal circles intersect such that each passes through the centre of the other. If the length of the common chord of the circles is 10?3 cm, then what is the diameter of the circle?


  • Options
  • A. 10 cm
  • B. 15 cm
  • C. 20 cm
  • D. 30 cm

  • Correct Answer
  • 20 cm 

    Explanation

    Let there be 2 circles with centre O1 and OAB is the common chord

    Since both passes through the center of each other as shown in figure

    So O1O is the radius of both

    Let O1O = r = AO1= AO

    AX = AB / 2 = 5?3 cm (since OX perpendicular to chord bisects it)

    AOO1 forms an equilateral triangle with on side = radius = r

    Sin 60 = ?3/2 = AX / AO = 5?3/r

    So r = 10 cm

    So diameter = 20 cm

     

  • Tags: Bank Exams

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    • Options
    • A. 12/?+4
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    • C. 3/?+4
    • D. 6/?+2?2
    • Discuss
    • 2. What is the value of 2+2+2+2.......

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    • A. 1
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    • 3. If (4a +7b) (4c-7d) = (4a -7b) (4c +7d, then which one of the following is correct ?

    • Options
    • A. a/b = c/d
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    • Options
    • A. xy
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    • Options
    • A. Each fraction is equal to 1 or -1
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    • C. Each fraction is equal to 1/2 or -1
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    • 6. If the mean of m observations out of n observations is n and the mean of remaining observations is m, then what is the mean of all n observations?

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    • A. 2m ?m^2/n
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