x2 ? 11x + 28=0
x2 ? 7x ? 4x + 28=0
x (x-7) ? 4 (x-7)=0
(x-4) (x-7)=0 x=4, 7
y2 ? 18y + 81=0
y2 ?9y ? 9y + 81=0
y (y-9) ? 9 (y-9)=0
(y-9) (y-9)=0 y=9, 9
So, x<y.
Case I : MW MW MW MW
Case II: WM WM WM WM
Let us arrange 4 men in 4! ways, then we arrange 4 women in 4P4 ways at 4 places either left of the men or right of the men. Hence required number of arrangements
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