Monday + Tuesday + Wednesday = 37 x 3 -----------(1)
Tuesday + Wednesday + Thursday = 34 x 3---------(2)
Thursday = 4/5 of Monday ------------------(3)
subtract eqn (1) from (2) we get,
Thursday - Monday = -9
=> Monday - Thursday = 9.......(4)
From (3) & (4), we get
So,Thursday = 36 C
Let the number of males be 'M'
Let the number of females be 'F'
From the given conditions,
(F-15)=2M.....(i)
F=5(M-45).....(ii)
By solving the equations (1) & (2) we get M = 80
Then substitute M = 80 in (1)
F = 2M + 15
F = 2 x 80 + 15
=> F = 175
Therefore, number of males = 80 and females = 175 in the party.
Given fraction is 5 (2/7) - 3 (1/14) - 2 (1/14) - 1 (1/7) = ? + 3 (1/17)
It can be written as
(5 - 3 - 2 - 1) + (2/7 - 1/14 - 1/14 - 1/7) = ? + 3 (1/17)
-1 + 0 - 3 (1/17) = ?
=> ? = -4 (1/17)
We know that
=>
According to BODMAS rule,
After multiplication only, addition is done.
Hence,
5 + 2 x 10 = 5 + 20 = 25.
The given inequality is 3p - 16 < 20
For solving this inequality, follow these steps
Now add 16 on both sides
we get 3p - 16 + 16 < 20 + 16
=> 3p < 36
Now divide the above eqn with 3 on both sides
we get, 3p/3 < 36/3
p < 12.
According to BODMAS Rule,
10 + 10(9)
= 10 + 90
= 100
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