Given exp = =
= =
= =78
Let F and C denotes the temparature in Fahrenheit anid Celcsius respectively.
Then, (F - 32) /(212 - 32) = (C - 0)/(100 - 0), if c = 35, then F = 95.
[15% of 300% of 560] × 2 ÷ 5
= (15 x 300 x 560 x 2)/100 x 100 x 5
~= 100
=>
We know that
Given fraction is 5 (2/7) - 3 (1/14) - 2 (1/14) - 1 (1/7) = ? + 3 (1/17)
It can be written as
(5 - 3 - 2 - 1) + (2/7 - 1/14 - 1/14 - 1/7) = ? + 3 (1/17)
-1 + 0 - 3 (1/17) = ?
=> ? = -4 (1/17)
Let the number of males be 'M'
Let the number of females be 'F'
From the given conditions,
(F-15)=2M.....(i)
F=5(M-45).....(ii)
By solving the equations (1) & (2) we get M = 80
Then substitute M = 80 in (1)
F = 2M + 15
F = 2 x 80 + 15
=> F = 175
Therefore, number of males = 80 and females = 175 in the party.
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