Given Expression = = = 2
x = y <=> 1 - q = 2q + 1 <=> 3q = 0 <=> q = 0.
2ab=
29-9=20
=>ab=10
Let the required two numbers be a, b
From the given data,
2a + 3b = 36 .....(1)
3a + 2b = 39 .....(2)
Now, by solving 1 and 2 eqnts, we get
5a = 45
a = 9 ....(3)
Put (3) in (1), we get
2(9) + 3b = 36
=> 18 + 3b = 36
3b = 36 - 18
=> b = 18/3 = 6
Required, difference between the numbers = a + b = 9 + 6 = 15.
Let 's' be the number of small packets and 'b' the number of large packets sold on that day.
Therefore, s + b = 5000 ... eqn (1)
Each small packet was sold for Rs.150.
Therefore, 's' small packets would have fetched Rs.150s.
Each large packets was sold for Rs.250.
Therefore, 'b' large packets would have fetched Rs.250b.
Total value of sale = 150s + 250b = Rs. 10.5 Lakhs (Given)
Or 150s + 250b = 10,50,000 ... eqn (2)
Multiplying equation (1) by 150, we get 150s + 150b = 7,50,000 ... eqn (3)
Subtracting eqn (3) from eqn (2), we get 100b = 3,00,000
Or b = 3000
We know that s + b = 5000
So, s = 5000 - b = 5000 - 3000 = 2000.
2000 small packets were sold.
Now,
50.003% of 99.8 ÷ 49.988 = ?
? ~= (50 x 100/100)/50
? ~= (50 x 100)/(100 x 50)
? ~= 1
=
Using BODMAS Rule,
First solve division, mutiplication and Addition
So here 10/2 = 5
Then 2 x 5 = 10
Now, 5 + 10 = 15.
Hence, 5 + 2 x 10/2 = 15.
Given,
5sinx + 12cosx ? -r
cosx) ? -r
= cosA => sinA =
=> 13(sinx cosA + sinA cosx) ? -r
=> 13(sin(x + A)) ? -r
we know that , -1 ? sin (angle) ? 1
=> 13sin (x + A) ? -13
Given a secret is told to 3 persons in 3 minutes.
And if the process continues with each person saying 3 other persons,
In 30 minutes => the rocess for 10 times because each person time is 3 minutes.
Required number of persons =
Now it forms a geometric progression,
Sum to n terms is
Here a = 3, r = 3
=> 59048 x 3 /2
= 88572.
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