Let the required two numbers be a, b
From the given data,
2a + 3b = 36 .....(1)
3a + 2b = 39 .....(2)
Now, by solving 1 and 2 eqnts, we get
5a = 45
a = 9 ....(3)
Put (3) in (1), we get
2(9) + 3b = 36
=> 18 + 3b = 36
3b = 36 - 18
=> b = 18/3 = 6
Required, difference between the numbers = a + b = 9 + 6 = 15.
Here sum is put on compound interest,
? P.W. = A / (1 + r / 100)n = 2420 / (1 + 10 / 100)2 = 2420 x 100 / 121 = Rs. 2000
? T.D. = P.W. - P
? True discount = 2420 - 2000 = Rs. 420
The Sum of the digits in each number, Except 324 is 10.
The given number series follows the pattern that,
24×0 + 4 = 4
4×1 + 9 = 13
13×2 + 16 = 42
42×3 + 25 = 151
151×4 + 36 = 640
Therefore, the odd number in the given series is 41
From the beginning, the next term comes by adding prime numbers in a sequence of 2, 3, 5, 7, 9, 11, 13... to its previous term. But 165 will not be in the series as it must be replaced by 166 since 153+13 = 166.
The given number series follows a pattern that
196, 169, 144, 121, 100, 81, ?
-27 -25 -23 -21 -19 -17
=> 81 - 17 = 64
Therefore, the series is 196, 169, 144, 121, 100, 81, 64.
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