Discussion
Home ‣ Aptitude ‣ Simplification Comments
- Question
The average number of visitors of a library in the first 4 days of a week was 58. The average for the 2nd, 3rd, 4th and 5th days was 60.If the number of visitors on the 1st and 5th days were in the ratio 8 : 9. Then what is the number of visitors on the 5th day of the library ?
Options- A. 54
- B. 64
- C. 68
- D. 72
- Correct Answer
- 72
ExplanationIf number of visitors on 1st, 2nd, 3rd, 4th & 5th day are k, l, m, n & o respectively, then
k + l + m + n = 58 x 4 = 232 ---- (i) &
l + m + n + o = 60 x 4 = 240 ---- (ii)
Subtracting (i) from (ii), we get
o-k = 8 ---(iii)
Given, k/o = 8/9 ----(iv)
So from (iii) & (iv), we get
a = 64, e = 72
Therefore, number of visitors on 5th day is 72. - 1. Given that 100.48 = x, 100.70 = y and xz = y2, then the value of z is close to ___ ?
Options- A. 3.7
- B. 2.7
- C. 3.6
- D. 2.9 Discuss
- 2. Simplify and find '?' 48?+32? = 320
Options- A. 4
- B. 8
- C. 16
- D. 32 Discuss
- 3. Solve this inequality 3b - 7 < 32?
Options- A. b = 13
- B. b < 13
- C. b > = 13
- D. b < = 13 Discuss
- 4. A man could buy a certain number of notebooks for Rs.300. If each notebook cost is Rs.5 more, he could have bought 10 notebooks less for the same amount. Find the price of each notebook ?
Options- A. 15
- B. 20
- C. 10
- D. 8 Discuss
- 5. 217 x 217 + 183 x 183 = ?
Options- A. 84521
- B. 87487
- C. 80578
- D. 78458 Discuss
- 6. Twenty times a positive integer is less than its square by 96. What is the integer ?
Options- A. 42
- B. 36
- C. 48
- D. 24 Discuss
- 7. In a slip test, K got the 15th rank and he was 44th from the bottom of the list of passed students. 4 students did not take up the slip test and 3 students were failed. What is the total strenght of the class ?
Options- A. 63
- B. 62
- C. 64
- D. 65 Discuss
- 8. Simplify the following : 373+353+283-3x37x35x28372+352+282-37x35-35x28-37x28 ?
Options- A. 100
- B. 1
- C. 4
- D. 0 Discuss
- 9. If 3x+7=x2+p=7x+5 , what is the value of P ?
Options- A. 17/2
- B. 25/3
- C. 33/4
- D. 41/5 Discuss
- 10. An owner of a Dry fruits shop sold small packets of mixed nuts for Rs. 150 each and large packets for Rs. 250 each. One day he sold 5000 packets, for a total of Rs. 10.50 lakh. How many small packets were sold ?
Options- A. 2000
- B. 3000
- C. 2500
- D. 3500 Discuss
Simplification problems
Search Results
Correct Answer: 2.9
Correct Answer: 16
Explanation:
given
=>
Now squaring on both sides
=>
=> 100 x ? = 1600
=> ? = 16
Correct Answer: b < 13
Explanation:
The given 3b - 7 < 32 can be solved as
3b - 7 < 32
3b < 39
b < 13.
Correct Answer: 10
Explanation:
Let the price of each note book be Rs.x.
Let the number of note books which can be brought for Rs.300 each at a price of Rs.x be y.
Hence xy = 300
=> y = 300/x
(x + 5)(y - 10) = 300 => xy + 5y - 10x - 50 = xy
=>5(300/x) - 10x - 50 = 0 =>
multiplying both sides by -1/10x
=>
=> x(x + 15) - 10(x + 15) = 0
=> x = 10 or -15
As x>0, x = 10.
Correct Answer: 80578
Explanation:
=
It is in the form of
= 2(40000 + 289) = 80578.
Correct Answer: 24
Explanation:
Let the integer be x. Then,
x2 - 20x = 96
(x + 4)(x - 24) = 0
x = 24
Correct Answer: 65
Explanation:
Total strength of the class is given by
15 + 44 + 4 + 3 - 1 = 65
Correct Answer: 100
Correct Answer: 17/2
Explanation:
Now,
Correct Answer: 2000
Explanation:
Let 's' be the number of small packets and 'b' the number of large packets sold on that day.
Therefore, s + b = 5000 ... eqn (1)
Each small packet was sold for Rs.150.
Therefore, 's' small packets would have fetched Rs.150s.
Each large packets was sold for Rs.250.
Therefore, 'b' large packets would have fetched Rs.250b.
Total value of sale = 150s + 250b = Rs. 10.5 Lakhs (Given)
Or 150s + 250b = 10,50,000 ... eqn (2)
Multiplying equation (1) by 150, we get 150s + 150b = 7,50,000 ... eqn (3)
Subtracting eqn (3) from eqn (2), we get 100b = 3,00,000
Or b = 3000
We know that s + b = 5000
So, s = 5000 - b = 5000 - 3000 = 2000.
2000 small packets were sold.
Comments
There are no comments.More in Aptitude:
Programming
Copyright ©CuriousTab. All rights reserved.