The given 3b - 7 < 32 can be solved as
3b - 7 < 32
3b < 39
b < 13.
Let the price of each note book be Rs.x.
Let the number of note books which can be brought for Rs.300 each at a price of Rs.x be y.
Hence xy = 300
=> y = 300/x
(x + 5)(y - 10) = 300 => xy + 5y - 10x - 50 = xy
=>5(300/x) - 10x - 50 = 0 =>
multiplying both sides by -1/10x
=>
=> x(x + 15) - 10(x + 15) = 0
=> x = 10 or -15
As x>0, x = 10.
=
It is in the form of
= 2(40000 + 289) = 80578.
Let, Hema attempted 'k' sum correctly, then
k x 3 -2 x(35-k) = 60
5k = 130
k = 26
so 26 correct sums.
Given that ,
=> x-y=3, x+y=5
=> x = 4
a+b=5 ...(1) and 3a+2b=20 ...(2)
Multiplying (1) by 2 and subtracting from (2), we get : a=10.
Putting a=10 in (1), we get : b=-5
Therefore, (3a+b) = 3 x 10+(-5)=30-5=25.
given
=>
Now squaring on both sides
=>
=> 100 x ? = 1600
=> ? = 16
If number of visitors on 1st, 2nd, 3rd, 4th & 5th day are k, l, m, n & o respectively, then
k + l + m + n = 58 x 4 = 232 ---- (i) &
l + m + n + o = 60 x 4 = 240 ---- (ii)
Subtracting (i) from (ii), we get
o-k = 8 ---(iii)
Given, k/o = 8/9 ----(iv)
So from (iii) & (iv), we get
a = 64, e = 72
Therefore, number of visitors on 5th day is 72.
Let the integer be x. Then,
x2 - 20x = 96
(x + 4)(x - 24) = 0
x = 24
Total strength of the class is given by
15 + 44 + 4 + 3 - 1 = 65
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